[英]What does “= !” in the following PHP code mean?
When i run the sql script and substitute it with a numbers it return empty or null 当我运行sql脚本并用数字替换它时,它返回空或null
$order_f = $dbs->query_field("SELECT order_id FROM orders WHERE order_center_id = !", $record['cust_id']);
What does the = ! 什么=! stand for? 代表? Is this not equal? 这不相等吗?
It's not an operator at all! 它根本不是运营商!
In your case it seems that the query_field()
method that's provided by your database object (which I think is based on MDB2 ) provides some kind of prepared statement, where exclamation marks are used for place holders. 在你的情况下,似乎你的数据库对象(我认为它基于MDB2 )提供的query_field()
方法提供了某种预备语句,其中感叹号用于占位符。 I'm imagining that the following query is executed based on your code: 我想是根据你的代码执行以下查询:
SELECT order_id FROM orders WHERE order_center_id = 123
Where 123
is the value of $record['cust_id']
. 其中123
是$record['cust_id']
。
Old answer 老答案
In your case !=
(or <>
) could be the same as =!
在你的情况下!=
(或<>
) 可能与=!
相同=!
(or = NOT(...)
), because "not equal to" might be considered the same as "equal to inverse of", but only for boolean value logic. (或= NOT(...)
),因为“不等于”可能被认为与“等于倒数”相同,但仅适用于布尔值逻辑。 It will not work when you compare strings. 比较字符串时它不起作用。
Also, there's a difference in operator precedence : 此外, 运营商优先级有所不同:
a = !b & c
This is evaluated as a = NOT(b) & c
. 这被评估为a = NOT(b) & c
。
a != b & c
Whereas this is evaluated as a = NOT(b & c)
. 而这被评估为a = NOT(b & c)
。
Q: What does the = ! 问:什么=! stand for? 代表? Is this not equal? 这不相等吗?
No. A not equals comparator would be foo != bar
or foo <> bar
不,A等于比较器就是foo != bar
或foo <> bar
I think you need to look at the query_field
function to figure out what that's doing. 我认为你需要查看query_field
函数来弄清楚它在做什么。 It looks like the query is intended to do an equals comparison, and that exclamation point is a placeholder. 看起来该查询旨在进行等于比较,并且该感叹号是占位符。 (I'm not familiar with that query_field
function; it doesn't look like a mysql_, mysqli_ or a PDO function, at least, that I've ever seen.) (我不熟悉query_field
函数;它看起来不像mysql_,mysqli_或PDO函数,至少,我见过。)
What is $dbs
? 什么是$dbs
? What kind of object is that? 这是什么样的对象? I bet that's where this method is defined. 我敢打赌,这就是定义这种方法的地方。
I suspect someone has added a layer, on top of mysql interface, to pseudo-support paramaterized queries. 我怀疑有人在mysql接口之上添加了一个伪支持参数化查询的层。 Likely, that second argument to the function gets run through mysql_real_escape_string, before it's included in the SQL text, replacing the bang (!). 可能,函数的第二个参数通过mysql_real_escape_string运行,在它包含在SQL文本中之前,替换了bang(!)。 That seems the most likely explanation. 这似乎是最可能的解释。
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