neo4j如何用Cypher返回所有节点标签？

Question

I can't find how to return a node labels with Cypher.

Anybody knows the syntax for this operation?

Answer 1

To get all distinct node labels:

MATCH (n) RETURN distinct labels(n)

To get the node count for each label:

MATCH (n) RETURN distinct labels(n), count(*)

Answer 2

有一个函数标签（节点）可以返回节点的所有标签。

Answer 3

If you want all the individual labels (not the combinations) you can always expand on the answers:

MATCH (n)
WITH DISTINCT labels(n) AS labels
UNWIND labels AS label
RETURN DISTINCT label
ORDER BY label

Answer 4

Neo4j 3.0 has introduced the procedure db.labels() witch return all available labels in the database. Use:

call db.labels();

Answer 5

 START n=node(*) RETURN labels(n)

Answer 6

If you're using the Java API, you can quickly get an iterator of all the Label s in the database like so:

GraphDatabaseService db = (new GraphDatabaseFactory()).newEmbeddedDatabase(pathToDatabase);
ResourceIterable<Label> labs = GlobalGraphOperations.at(db).getAllLabels();

Answer 7

If you want to get the labels of a specify node, then use labels(node) ; If you only want to get all node labels in neo4j, then use this function instead: call db.labels; , never ever use this query: MATCH n RETURN DISTINCT LABELS(n) . It will do a full table scan, which is very very slow..