golang类型转换不起作用（I）预期

Question

I'm using go-flags to parse command line options.

Per the go-flags docs: "... [if] either -h or --help was specified in the command line arguments, a help message will be automatically printed. Furthermore, the special error type ErrHelp is returned."

The method I'm calling is:

func (p *Parser) Parse() ([]string, error) {

I'm calling it with:

var opts struct {
    // ...
}

func main() {

    parser := flags.NewParser(&opts, flags.Default)

    args, err := parser.Parse()

A snippet from the file that defines ErrHelp looks like this:

type ErrorType uint

const (
    // Unknown or generic error
    ErrUnknown ErrorType = iota

    // Expected an argument but got none
    ErrExpectedArgument

    // ...

    // The error contains the builtin help message
    ErrHelp

    // ...
)

// Error represents a parser error. The error returned from Parse is of this
// type. The error contains both a Type and Message.
type Error struct {
    // The type of error
    Type ErrorType

    // The error message
    Message string
}

// Get the errors error message.
func (e *Error) Error() string {
    return e.Message
}

func newError(tp ErrorType, message string) *Error {
    return &Error{
        Type:    tp,
        Message: message,
    }
}

So they have this custom "Error" type. And in the Parse() method above, internally, the error is getting created with a block of code like this:

    help.ShowHelp = func() error {
        var b bytes.Buffer
        p.WriteHelp(&b)
        return newError(ErrHelp, b.String())
    }

As you can see newError() returns "*Error" as it's type. But the anonymous function just above returns type "error" - so those types must be compatible.(?)

But now back to the original problem - I'm just trying to see if my "err" is an "Error" and has member "Type" equal to ErrHelp. So I try this:

if err != nil && flags.Error(err).Type == flags.ErrHelp {

Or even just this:

fmt.Printf("test:", flags.Error(err))

And either way the compiler gives me:

main.go:37: cannot convert err (type error) to type flags.Error

But does not state why that conversion can't be done. Any ideas?

(I don't get how "*Error" successfully converts to "error" in the anonymous function above, and I even more don't get why if that works then I can't convert it back the other way... I must be missing something really dumb here, but I'm not seeing what it is.)

Answer 1

An error is an interface with a single method Error() string . See http://golang.org/pkg/builtin/#error

A flags.Error has such a method, so it can be used as an error .

Conversely, however, a flags.Error is a struct, and there's no way to convert an arbitrary value to a struct.

What you can do is, and I think this is the answer to your question, is that if you've got a flags.Value inside an error , then you can cast the error back to the underlying type. The syntax for that is e := err.(*flags.Error) . This'll give you a value of type *flags.Error (or panic, if the underlying type isn't *flags.Error ). You can avoid the panic in this case by using the comma-ok form, which is e, ok := err.(*flags.Error) .

Concretely, you would write:

  args, err := flags.Parse()
  if err != nil {
     if ferr, ok := err.(*flags.Error); ok {
       // ... something using ferr
     } else {
       // ... deal with non-flags.Error case, if that's possible.
     }
  }