更新函数内部的xml elemnt。 如何在函数内部传递元素

Question

showOrUpdate($day->Date, $_POST['Date'])

and function:

function showOrUpdate($element, $value)
{
    if (isset($value) && !empty($value))
    {   
        $element = $value;
    } 

    return $element;
}

but problem is that $element is not passed as element but is passed as readable value and is then for example 2013-08-22 and not $day->Date .

but I want to pass it in function and inside function update value and later save it.

like:

$day->Date =  $value;

Is this possible?

Answer 1

What you are referring to is commonly know as pass by reference. When defining a function use the '&' sign for variables that you want to pass by reference.

function showOrUpdate(&$element, $value) {
  if (isset($value) && !empty($value))   
    $element = $value; 
}

This would update the original value of $element. Also, in this situation you don't need to use a return statement as the variable has already been modified within the function itself.