Bash脚本，用于在文本文件中列出子目录和文件

Question

I need a Script that writes the directory and subdirectory in a text-file.

For example the script lies in /Mainfolder and in this folder are four other folders. Each contains several files.

Now I would like the script to write the path of each file in the textfile.

Subfolder1/File1.dat
Subfolder1/File2.dat
Subfolder2/File1.dat
Subfolder3/File1.dat
Subfolder4/File1.dat
Subfolder4/File2.dat

Important is that there is no slash in front of the listing.

Answer 1

Use the find command:

find Mainfolder > outputfile

and if you only want the files listed, do

find Mainfolder -type f > outputfile

You can also strip the leading ./ if you search the current directory, with the %P format option:

find . -type f -printf '%P\n' > outputfile

Answer 2

If your bash version is high enough, you can do it like that:

#!/bin/bash
shopt -s globstar
echo ** > yourtextfile

Answer 3

This solution assumes that the subdirectories contain only files -- they do not contain any directory in turn.

find . -type f -print | sed 's|^.*/S|S|'

I have created a single file in each of the four subdirectories. The original output is:

./Subfolder1/File1.dat
./Subfolder4/File4.dat
./Subfolder2/File2.dat
./Subfolder3/File3.dat

The filtered output is:

Subfolder1/File1.dat
Subfolder4/File4.dat
Subfolder2/File2.dat
Subfolder3/File3.dat

Answer 4

You can use this find with -exec :

find . -type f -exec bash -c 'f="{}"; echo "${f:2}"' \;

This will print all files starting from current paths by removing ./ from front.