[英]MYSQL SUBSTRING_INDEX / CONVERT / IF clause
I have a table with something like this. 我有这样的桌子。
abc-cde-0001222
abc-cde-0001223
abc-ced-0001224
cde-efg-0003001
ced-efg-0003002
ced-efg-0003008
I wish to select abc-cde-0001222, abc-ced-0001224
我希望选择
abc-cde-0001222, abc-ced-0001224
also cde-efg-0003001 , cde-efg-0003002
ced-efg-0003008 , ""
See, I need to obtain 1st and last values of a range. 看,我需要获取范围的第一个和最后一个值。 If the particular value is only one item (not in a range) I want it to select as the 1st value and a null value.
如果特定值只是一项(不在范围内),我希望它选择为第一值和空值。
So far I have only a Idea of using IF
and increment operator
(If this is possible). 到目前为止,我只有使用
IF
和increment operator
的想法(如果可能的话)。 I can do the formatting and obtain the Int value using 我可以使用以下格式进行格式化并获取Int值
SELECT field, CONVERT(SUBSTRING_INDEX(field,'-',-1), UNSIGNED INTEGER) AS num
FROM table
ORDER BY num;
Please could you give me a hand... Lot appreciated 请你帮我一下...非常感谢
This is a pain in MySQL. 这是MySQL的痛苦。 But, it is possible.
但是,有可能。 The logic is to find where a sequence starts.
逻辑是查找序列从何处开始。 You can do this with a correlated subquery and some arithmetic.
您可以使用相关的子查询和一些算法来做到这一点。 Then you want a cumulative sum of the starts.
然后,您需要起点的累积总和。 This is harder, because it requires doing a correlated subquery on the correlated subquery.
这比较困难,因为它需要对相关子查询执行相关子查询。
First, to set the NullIfStart
variable: 首先,设置
NullIfStart
变量:
select t.*,
(select 0
from t t2
where left(t2.field, 8) = left(t.field, 8) and
t2.field < t.field and
right(t2.field, 7) + 0 = right(t.field, 7) + 0 - 1
) as NullIfStart
from t;
This gets the cumulative sum, which can be used as a grouping field: 这将获取累积总和,可以将其用作分组字段:
select t.*
(select sum(NullIfStart is null)
from (select t1.*,
(select 0
from t t2
where left(t2.field, 8) = left(t1.field, 8) and
t2.field < t1.field and
right(t2.field, 7) + 0 = right(t1.field, 7) + 0 - 1
) as NullIfStart
from t t1
) tnis
where right(tnis.field, 7) = right(t.field, 7) and
tnis.field <= t.field
) grp
from t;
The final solution is to do the aggregation: 最终的解决方案是进行聚合:
select min(field),
(case when max(field <> min(field) then max(field) end)
from (select t.*
(select sum(NullIfStart is null)
from (select t1.*,
(select 0
from t t2
where left(t2.field, 8) = left(t1.field, 8) and
t2.field < t1.field and
right(t2.field, 7) + 0 = right(t1.field, 7) + 0 - 1
) as NullIfStart
from t t1
) tnis
where left(tnis.field, 8) = left(t.field, 8) and
tnis.field <= t.field
) grp
from t
) s
group by left(s.field, 8), grp;
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