[英]Is it possible to create ByteBuffer from a List<ByteBuffer>?
Let's say i have a list/arrayList or an array of ByteBuffers ( List<ByteBuffer>
or ByteBuffer[]
) 假设我有一个list / arrayList或ByteBuffers数组(
List<ByteBuffer>
或ByteBuffer[]
)
It is possible from this to directly get the bytes from the above array without iterating through all the items or computing their total size? 从中可以直接从上面的数组中获取字节而不迭代所有项目或计算它们的总大小? I am looking for something like this:
我正在寻找这样的东西:
ByteBuffer[] bufferList = new ByteBuffer[7]; //this can be any kind of list of ByteBuffers
//add items to the array
ByteBuffer buffer = (ByteBuffer) bufferList; //what i want to achieve
Of course the last line is not correct. 当然最后一行不正确。
The thing is that i already have in the array all the bytes in order, but I want them not to be in a list anymore, but in a single ByteBuffer. 问题是我已经在数组中按顺序包含所有字节,但是我希望它们不再在列表中,而是在单个ByteBuffer中。 So is there something that makes possible to create a ByteBuffer from a list/array of ByteBuffers?
那么是否有可能从ByteBuffers的列表/数组创建ByteBuffer?
Thank you! 谢谢!
public ByteBuffer convertToOne(ByteBuffer[] src)
{
int size=0;
for(int i = 0 ; i < src.length ; i++) {
size+=src[i].array().length;
}
ByteBuffer newBuffer = ByteBuffer.allocate(size);
int sizeAt = 0;
for(int i = 0 ; i < src.length ; i++) {
newBuffer.put(src[i].array(), sizeAt);
sizeAt += src[i].array().length;
}
return newBuffer;
}
I believe you're going to have to create a new ByteBuffer
and copy each of the buffers in bufferList
into the new one. 我相信你将不得不创建一个新的
ByteBuffer
并将bufferList
每个缓冲区bufferList
到新的缓冲区中。 You should put this functionality in a method so as to not repeat the code each time you use it. 您应该将此功能放在方法中,以便每次使用时都不重复代码。
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