[英]How exactly does this Sed command work?
sed 's@.*/.*\.@.@'
The command is part of a larger command to find all file extensions in a directory. 该命令是查找目录中所有文件扩展名的较大命令的一部分。
find . -type f -name '*.*' | sed 's@.*/.*\.@.@' | sort | uniq
I understand that find
returns all files with an extension, I understand that sed returns just the extensions and then sort/uniq are self-explanatory. 我理解
find
返回所有带扩展名的文件,我知道sed只返回扩展名,然后sort / uniq是不言自明的。
At first, I was confused about the @
symbol, but my best guess now guess is that it is part of Regex. 起初,我对
@
符号感到困惑,但我现在最好的猜测是它是Regex的一部分。
What really confuses me is a can't figure how it explicitly works, and the closest matching syntax I can find in a manual is s/regexp/new/
which still doesn't match the syntax of the command. 让我感到困惑的是无法确定它是如何显式工作的,而我在手册中找到的最接近的匹配语法是
s/regexp/new/
仍然与命令的语法不匹配。
In the s/regexp/replacement/
syntax, the /
can be replaced by any other character, such as ,
, :
, @
, etc. This is very useful if your regexp itself contains /
characters, such as your example of .*/.*\\.
在
s/regexp/replacement/
语法中, /
可以使用任何其他字符代替,比如,
, :
, @
等,这是如果你的正则表达式本身就含有非常有用的/
字符,比如你的例子.*/.*\\.
. 。
Your command could be simplified a bit, though: 但是,您的命令可以简化一点:
find . -type f -name '*.*' | sed 's/.*\././' | sort -u
Here, I simplified the regexp so that it no longer contains a /
character. 在这里,我简化了正则表达式,使其不再包含
/
字符。
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