在分配A（I）= B中，B和I中的元素数必须相同

Question

I input 'test' as the string, phrase, and it gives me the following error:

    >> CreateBarcodePattern('test')
In an assignment  A(I) = B, the number of elements in B and I must be the same.

Error in CreateBarcodePattern (line 5)
    p(i) = code128B{find(ismember(code128B,phrase(i)))-109,3};

The function CreateBarcodePattern is as follows:

function [p] = CreateBarcodePattern(phrase)
load('code128B');
p = [];
for i = 1:length(phrase)
    p(i) = code128B{find(ismember(code128B,phrase(i)))-109,3};
end

I put a break point at line 5 and at the point i = 1, p = [] (and empty array so far), code128B = <108x3 cell> (A 108 by 3 cell full of strings), and phrase = 'test'. The very next line gives me the error above. I tried doing:

load('code128B.mat')
p = [];
phrase = 'test';
p(1) = find(ismember(code128B,phrase(1)))-109;
p(1) = code128B{p(1),3}

but at the last line the error:

In an assignment  A(I) = B, the number of elements in B
and I must be the same.

is again given. Right before the error, p = 84 which is what I am expecting, this is due to the previous line, p(1) = fi... The line:

code128B{find(ismember(code128B,'t'))-109,3};

Returns the correct variable so I know this much works. It just doesn't work when I'm iterating it. How can I fix this?

Answer 1

Maybe the line

find(ismember(code128B,phrase(1)))

is returning more than 1 index. p(1) wants exactly one element.

If you just want the first index, then do something like this:

Idx = find(ismember(code128B,phrase(1)));
Idx = sort(Idx); % Am just assuming you need to sort!
p(1) = Idx(1) - 109;
p(1) = code128B{p(1),3}

Answer 2

I found the answer:

p(i) = code128B{find(ismember(code128B,phrase(i)))-109,3};
p(i) = str2num(code128B{find(ismember(code128B,phrase(i)))-109,3});