从DLL获取程序汇编

Question

I would like to access a function of a program from which is attached a DLL.

In DLL I've tried:

Assembly assembly = Assembly.GetExecutingAssembly();
Type type = assembly.GetType("Uranium");
MethodInfo methodInfo = type.GetMethod("Util");

methodInfo.Invoke("SendClient", new object[] { Packet.GetData()});

But not works I get a null exception but not say the line. The running program is called and namespace is 'Uranium', the class is 'Util' and function is 'SendClient'.

Answer 1

I have been able solve it on my own.

Code:

Assembly assembly = Assembly.LoadFrom("Uranium.exe");
Type type = assembly.GetType("Uranium.Util");
MethodInfo methodInfo = type.GetMethod("SendClient");

methodInfo.Invoke(null, new object[] { Packet.GetData() });

Answer 2

You first need to find the assembly that contains the type. Also, you need to pass the class name to GetType() , not the namespace, and method name to GetMethod() , not class name.

foreach (Assembly currentassembly in AppDomain.CurrentDomain.GetAssemblies()) 
{
    Type t = currentassembly.GetType("Util", false, true);
    if (t != null) 
    {
        MethodInfo methodInfo = type.GetMethod("SendClient");
        methodInfo.Invoke(Activator.CreateInstance(t),new object[] { Packet.GetData()});
    }
}

Answer 3

From what I can read from the code you've posted you try to invoke the function Util of class Uranium. And you're passing a string as the instance of the class.

This should be more like what you're trying to do:

Assembly assembly = Assembly.GetExecutingAssembly();
Type type = assembly.GetType("Util");
MethodInfo methodInfo = type.GetMethod("SendClient");

methodInfo.Invoke(Activator.CreateInstance(type), new object[] { Packet.GetData()});

If SendClient is a static member function then Activator.CreateInstance(type) can be replaced with null . And of course you should add checks that the GetType and GetMethod return values are not null