[英]Implicit Argument Passing in Python?
The code below is from hackermeter.com and I'm not sure what to think of it. 下面的代码来自hackermeter.com,我不知道该怎么想。 Is the variable i being passed implicitly to run() or does it expect more modification than just where it specifies?
变量i是隐式传递给run()还是期望更多修改而不是它指定的位置?
import sys
def run():
# Code here!
for i in range(int(sys.stdin.readline())):
run()
I'd argue that this is a poor coding practice. 我认为这是一个糟糕的编码实践。 The only reason
run()
has access to i
is that i
is global. run()
访问i
的唯一原因是i
是全球性的。
The following is arguably better as it will force the programmer to pass i
into run()
explicitly (if required): 以下可以说是更好,因为它会强制程序员明确地将
i
传递给run()
(如果需要):
import sys
def run():
# Code here!
def main():
for i in range(int(sys.stdin.readline())):
run()
if __name__ == '__main__':
main()
This is the code in the question: 这是问题中的代码:
import sys
def run():
# Code here!
for i in range(int(sys.stdin.readline())):
run()
i
is defined in global scope (that is at the top level of the module), and so is accessible inside run
. i
在全局范围内定义(即在模块的顶层),因此可以在run
访问。 This is because essentially only functions and classes introduce a new local scope, so an iteration variable is a normal variable of its enclosing scope. 这是因为基本上只有函数和类引入了一个新的局部作用域,因此迭代变量是其封闭作用域的正常变量。
If run
does access i
, this creates the potential for an error if i
has not already been defined (eg if a conditional statement prevented the loop from being executed at all). 如果
run
不接i
,这对于一个错误造成如果潜在的i
尚未确定(例如,如果一个条件语句防止从所有正在执行的循环)。
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