多个复选框显示/隐藏DIV

Question

I am trying to show/hide a form inside a div, conditional on multiple checkboxes. 我试图在div中显示/隐藏一个表单，条件是多个复选框。 If all 3 are checked, the div contents should appear. 如果选中全部3，则应显示div内容。 If one or more are unchecked, the div contents should be hidden. 如果取消选中一个或多个，则应隐藏div内容。

<!DOCTYPE html>
<html lang="en">
    <head>
        <link href="style/bootstrap.css" rel="stylesheet">
        <script src="js/jquery.js"></script>
        <script>
            if ($('#checkbox1, #checkbox2, #checkbox3').is(:checked)) {
               $('#purchaseForm').show();
            } else {
               $('#purchaseForm').hide();
            }
        </script>
    </head>
    <body>
        <div class="span6">
            I understand that...<br>
            I understand that...<br>
            I understand that...<br><br>

        <div id="purchaseForm">
            [form]
        </div>          
        </div>

        <div class="span6">
            <input name="checkbox1" id="checkbox1" value="" type="checkbox"><br>
            <input name="checkbox2" id="checkbox2" value="" type="checkbox"><br>
            <input name="checkbox3" id="checkbox3" value="" type="checkbox"><br>
        </div>
    </body>
</html>

Answer 1

You are currently checking to see if any of the checkboxes are checked. 您当前正在检查是否已选中任何复选框。 Make sure they're all checked. 确保他们都被检查过。

if ($('#checkbox1').is(':checked') && $('#checkbox2').is(':checked') && $('#checkbox3').is(':checked'))

Answer 2

You can listen to the change event of checkboxes DEMO Here : 您可以在此处收听复选框DEMO的更改事件：

$(function(){
var container = $('#container');
var purchaseForm = $('#purchaseForm');
    container.on('change', 'input[type="checkbox"]', function(){
        if(container.find('input[type="checkbox"]').not(':checked').length){
        purchaseForm.hide();
        }
        else{
        purchaseForm.show();
        }
    });
    container.find('input[type="checkbox"]:first').change();
});

Answer 3

DEMO DEMO

$(function(){  
  var $cbx  = $(':checkbox[id^=check]'),
      $form = $('#purchaseForm');  
  $cbx.change(function(){
    $form[$cbx.not(':checked')[0]?'hide':'show']();
  }).change();
});

Answer 4

Try 尝试

$(document).ready(function() {
var a = $("#checkbox1");
var b = $("#checkbox2");
var c = $("#checkbox3");
var combined = a.add(b).add(c);
$(combined).click(function() //anyone of combined cliecked event
{
    // if ($('#checkbox1, #checkbox2, #checkbox3').is(':checked'))    this means         one of those is checked
    if ($(a).is(':checked') && $(b).is(':checked') && $(c).is(':checked')) {
        $('#purchaseForm').show();
    } else {
        $('#purchaseForm').hide();
    }
});

});

Answer 5

Try 尝试

jQuery(function(){
    var checks = $('#checkbox1, #checkbox2, #checkbox3');

    checks.click(function(){
        if (checks.filter(':checked').length == checks.length) {
            $('#purchaseForm').show();
        } else {
            $('#purchaseForm').hide();
        }
    }).triggerHandler('click')


})

Demo: Fiddle 演示：小提琴

多个复选框显示/隐藏DIV

问题描述

5 个解决方案

解决方案1
1 2013-08-29 03:00:40

解决方案2
1 2013-08-29 03:01:32

解决方案3
1 2013-08-29 03:12:43

解决方案4
1 2013-08-29 03:43:29

解决方案5
0 已采纳 2013-08-29 02:59:46

多个复选框显示/隐藏DIV

问题描述

5 个解决方案

解决方案1 1 2013-08-29 03:00:40

解决方案2 1 2013-08-29 03:01:32

解决方案3 1 2013-08-29 03:12:43

解决方案4 1 2013-08-29 03:43:29

解决方案5 0 已采纳 2013-08-29 02:59:46

解决方案1
1 2013-08-29 03:00:40

解决方案2
1 2013-08-29 03:01:32

解决方案3
1 2013-08-29 03:12:43

解决方案4
1 2013-08-29 03:43:29

解决方案5
0 已采纳 2013-08-29 02:59:46