[英]Query to return rows in date range but return only max value of column
What I want to do is select the price from a table where the date given is between the start and finish date in a table. 我想要做的是从表中选择价格,其中给定的日期在表格中的开始日期和结束日期之间。
SELECT price
FROM table
WHERE 'dategiven' BETWEEN startdate AND enddate
This is easy enough with a datetime filter. 使用日期时间过滤器很容易。 Problem is I have multiple records in the time window provided, I have a version column as well.
问题是我在提供的时间窗口中有多个记录,我也有一个版本列。
I have below an example of my table: 我有一个我的表的例子:
I want my query output to be as below where my dategiven
is 2013-08-25
我希望我的查询输出如下所示我的
dategiven
是2013-08-25
Milk has 3 records, 2 of them are valid for dategiven
(2013-08-25). 牛奶有3条记录,其中2条对
dategiven
有效(2013-08-25)。 I then want to return the result with the highest version? 然后我想以最高版本返回结果?
something like: 就像是:
SELECT
price
FROM table
WHERE 'dategiven' BETWEEN startdate AND enddate AND max(version)
Using the row_number()
function to rank the rows 使用
row_number()
函数对行进行排名
select product, price, version
from
(
select
*,
row_number() over (partition by product order by version desc) rn
from yourtable
where @dategiven between startdate and enddate
) v
where rn = 1
May not be the most efficient way but: 可能不是最有效的方式,但:
select price
from table
where
'dategiven' between startdate and enddate
and version =
(
select max(version) from table t2 where t2.product = table.product
and 'dategiven' between startdate and enddate
)
You can also try this 你也可以试试这个
select t.product, t.price, version
from table t
inner join
(select product, max(version) maxVerion from table where
'dategiven' between startdate and enddate group by product) temp
on temp.product = t.product and t.version = temp.maxVerion
Hope it helps. 希望能帮助到你。
my computer installed is not sqlservert but mysql. 我安装的电脑不是sqlservert而是mysql。 I do not know it is complex.
我不知道它很复杂。
select t.product, t.price, v.version
(
select temp.product, max(temp.version) as version
from
(
select product, price, startDate, endDate, version
from Table
where 'dategiven' between startDate and endDate
) as temp
group by temp.product
) as v
inner join Table as t
on v.version = t.version
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