[英]setBackGroundRGB not accepting string
The class setBackgroundRGB()
works if I pass it a literal类
setBackgroundRGB()
如果我传递给它一个文字
setBackgroundRGB(255,255,255);
but if I pass it a variable instead, it fails:但是如果我改为传递一个变量,它就会失败:
_Color = "255, 255, 255";
setBackgroundRGB(_Color);
Does not work and returns an error不起作用并返回错误
`Cannot find method setBackgroundRGB(string)`
Do i need to do some kind of conversion here that I am not aware of?我是否需要在这里进行某种我不知道的转换?
You need to pass an array. 你需要传递一个数组。 The following should work:
以下应该有效:
_Color = [255, 255, 255];
setBackgroundRGB(_Color);
Note - this is essentially what the post above is doing -- split() converts strings to arrays... 注意 - 这基本上就是上面的帖子 - split()将字符串转换为数组......
You are passing a string. 你正在传递一个字符串。 It takes integers.
它需要整数。
Try This: 尝试这个:
_Color = 255,255,255
I doubt that will work however. 我怀疑它会起作用。 You may need to do multiple variables for each
您可能需要为每个变量执行多个变量
red = 255;
green = 255;
blue = 255;
Indeed the API does not have a method setBackgroundRGB(string), provides a method setBackgroundRGB(Integer, Integer, Integer) , however, an option to achieve what you need, having a string as input is: 实际上API没有方法setBackgroundRGB(string),提供了一个方法setBackgroundRGB(Integer,Integer,Integer) ,但是,一个选项可以实现你所需要的,输入一个字符串是:
function setColorToRange() {
var colorRGB = '0, 255, 0';
var ss = SpreadsheetApp.getActiveSpreadsheet();
var sheet = ss.getActiveSheet();
var range = sheet.getRange('A1:B3');
range.setBackgroundRGB.apply(range, colorRGB.split(', '));
}
UPDATE UPDATE
To get the vector can be applied several improvements, widening a little the example presented, we integrate some of the improvements indicated in the comments, resulting in the following: 为了获得向量可以应用几个改进,扩展一些示例,我们整合了注释中指出的一些改进,产生以下结果:
function setColorToRange() {
var colorRGB = '0, 255, 0';
var ss = SpreadsheetApp.getActiveSpreadsheet();
var sheet = ss.getActiveSheet();
var range = sheet.getRange('A1:B3');
var arrColorRGB = getRGB(RGBString);
range.setBackgroundRGB.apply(range, arrColorRGB);
}
function getRGB(RGBString) {
// Returns a vector of integers
return RGBString.replace(/ /g, '').split(',').map(returnInt);
}
function returnInt(value) {
return parseInt(value, 10);
}
Just another variant of the same approach using range and RGBstring as parameters : 使用范围和RGBstring作为参数的相同方法的另一种变体:
function test(){ // to define 2 parameters
var range = SpreadsheetApp.getActiveSheet().getRange('A1:B3');
setColorToRange(range,'0, 255, 0');
}
function setColorToRange(range,RGBString) {
var colorRGB = RGBString.replace(/ /g,'').split(',');// first remove spaces if present then split on comma only to get the array of integers
range.setBackgroundRGB.apply(range, colorRGB);
}
const rgb = { red : 224, green : 224, blue : 224 } const rgb = { 红色:224,绿色:224,蓝色:224}
....setBackgroundRGB(rgb.red, rgb.green, rgb.blue); ....setBackgroundRGB(rgb.red, rgb.green, rgb.blue);
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