[英]Match empty lines in a file with 'grep'
Why does为什么
grep -c '^\n' myfile.txt
return 0 when there are empty lines in the file?当文件中有空行时返回 0 ?
If there is an empty line, it starts with a new line, right?如果有一个空行,它会从一个新行开始,对吗?
Please correct me if I am wrong.如果我错了,请纠正我。
匹配行尾的正则表达式是$
,而不是\\n
(因为grep
一次只处理一行,它会忽略行之间的换行符)。
grep -c '^$' myfile.txt
grep and count empty lines like this: grep 并像这样计算空行:
grep -c "^$" myfile.txt
As \\n
is considered end of line you need to use line start and line end "^$"
由于\\n
被视为行尾,因此您需要使用行开始和行结束"^$"
The other answers with -c
are correct. -c
的其他答案是正确的。
If you want to see what number is the empty line in the file:如果要查看文件中的空行是多少:
grep -n '^$' myfile.txt
For example:例如:
grep -n '^$' /usr/share/wordlists/rockyou.txt
4751:
34329:
50383:
99361:
154363:
231236:
562997:
2459758:
14344383:
14344384:
14344385:
(If you want to remove them: sed -i '/^$/d' myfile.txt
) (如果你想删除它们: sed -i '/^$/d' myfile.txt
)
:) :)
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