选择一个程序，Windows将按批处理文件打开具有特殊格式的文件

Question

(sorry by the english)

I have a app that uses the following command to open files:

java.awt.Desktop.getDesktop().open(new File(caminhoArquivo));

the problem is that i uses a special format to open files (ex.: .TXZ), and if i don´t open the file before by SO and says that i want to open that file whit notepad, the app just give a Excption and don´t open..

I´m needing to install this by command like .bat, and add in the registry of windows that i want to open this files in format .XXX by notepad..

Searching here, i found this examples:

Key: HKLM\SOFTWARE\Classes\.TXZ
Value: <default> = “TXZ.Document”

Key: HKLM\SOFTWARE\Classes\TXZ.Document
Value: <default> = “TXZ Document”

Key: HKLM\SOFTWARE\Classes\TXZ.Document\DefaultIcon
Value: <default> = “[!notepad.exe],0?

Key: HKLM\SOFTWARE\Classes\TXZ.Document\shell\open\command
Value: <default> = “[!notepad.exe]” “%1?

and this:

[HKEY_CURRENT_USER\Software\Classes\blergcorp.blergapp.v1\shell\open\command]
@="c:\path\to\app.exe \"%1\""
[HKEY_CURRENT_USER\Software\Classes\.blerg]
@="blergcorp.blergapp.v1"

but how is the first time that i uses something like this, i can´t do my .bat looking like this works.. someone can help me with one example?

Answer 1

要使用记事本批量打开文件* .xxx，请使用assoc .xxx=txtfile txt文件（您知道* .txt使用记事本打开，您可以使用assoc .txt进行窥视）要“取消关联”，请使用assoc .xxx=

Answer 2

assoc .txz=TXZfile assoc TXZfile=TXZfile ftype TXZfile="%SystemRoot%\system32\NOTEPAD.EXE" "%1"