C ++线程休眠而不冻结当前线程

Question

I have writing an application an I need to sleep new thread without stopping executing of current one.

Some code from application:

PlaySound(L"sounds\\started.wav", NULL, SND_FILENAME);
thread photos(makeScreens);
photos.join();
CONSOLE_Print("Some testing string");

And function that should work asynchronous:

void makeScreens(){
    CONSOLE_Print("Make Screens entered");
    srand (time(NULL));
    CONSOLE_Print("Sleeping 30s");
    Sleep(30000);
    CONSOLE_Print("Wake up");
    long int delay;
    for(int i=0; i<5; i++){ //loop for max screens=5
        delay=rand() % 600000 + 60000; //random a delay beetween sreens from 1 to 10 minutes
        CONSOLE_Print("Sleeping "+delay/1000);
        Sleep(delay); //sleep 
        CONSOLE_Print("Wake up and make screen");
        gdiscreen(i); //take a screen
    }
}

So I want to run makescreens() without stopping current execution of app. My output should be like this:

Some testing string
Make Screens entered
Sleeping 30s
Wake up
Sleeping xxxx
Wake up and make screen

How to fix it? Is there any other way instead of using sleep? I'm nawbie in c++.

Answer 1

Don't call photos.join(); .

This will make your main thread wait until the photo thread is finished.

Answer 2

join means that the main thread (which launched new thread) waits for launched thread to finish before proceeding. So the ordering below should meet your printing order requirement.

PlaySound(L"sounds\\started.wav", NULL, SND_FILENAME);
CONSOLE_Print("Some testing string");
thread photos(makeScreens);
photos.join();
CONSOLE_Print("new thread has now finished running");