在ajax发布中发送json字符串

Question

var myData = JSON.stringify($('form').serializeArray());

$.ajax({ 
    cache: false,
    url: "http://localhost/Demo/store.php",
    type: "POST",
    data: myData,           
    complete: function (xhr, status) {
        if (status === 'error' || !xhr.responseText) {
            alert(status);              
        }
        else {
            var r = xhr.responseText;                       
        }
    }
});

$decoded = json_decode($_REQUEST['myData'],true);
print_r($_REQUEST);
exit;

if (is_array($decoded))
{
    foreach ($decoded as $value) {
        echo $value["name"] . "=" . $value["value"];
    }
}

When i am trying to decode the data in php the error is undefined index myData..Please help me..Thanks.

Answer 1

试试看：

$decoded = json_decode($_POST['myData'],true);

Answer 2

Try this when call ajax

data: {'myData' : myData},

Then access using

json_decode($_POST['myData'],true); 

or

json_decode($_REQUEST['myData'],true);

Answer 3

try this pass datatype :

$.ajax({
    url: 'http://localhost/Demo/store.php',
    type: 'POST',
    dataType: 'json',
    data: $('#form').serialize(),
    success: function(xhr, status) {
    if (status === 'error' || !xhr.responseText) {
        alert(status);              
    }
    else {
        var r = xhr.responseText;                       
    }
}
});

Answer 4

When you pass a string as the data property is just appends it as a parameter query string to the URL. If you want to send an encoded JSON string you still need to give it a name:

data: {myData: myData}

Now you can use the myData request parameter in your PHP script.

Answer 5

used dataType:json; tosend json.