在Python中获取最小值和最大值之间的值

Question

I wan't to get a value if it's between min and max values. If the value is smaller than min, I want to get the min value and if it's greater than max I want to get the max. I use this code now, but is there an inbuilt or smarter way to do it?

def inBetween(minv, val, maxv):
  if minv < val < maxv: return val
  if minv > val:        return minv
  if maxv < val:        return maxv

print inBetween(2,5,10) 

Answer 1

Using min , max :

>>> def inbetween(minv, val, maxv):
...     return min(maxv, max(minv, val))
... 
>>> inbetween(2, 5, 10)
5
>>> inbetween(2, 1, 10)
2
>>> inbetween(2, 11, 10)
10

Answer 2

For the record: This kind of function is usually called clamp (as in clamping ), sometimes clip . The signature you mostly find for this is clamp(val, minv, maxv) . If you don't like the idiomatic solution using the functions min and max because of the function overhead, you may use this solution:

def clamp(val, minv, maxv):
    return minv if val < minv else maxv if val > maxv else val

A quick'n'dirty performance check:

>>> import timeit
>>> timeit.timeit("clamp(1, 5, 10)", "def clamp(val, minv, maxv): return min(maxv, max(minv, val))")
1.8955198710000332
>>> timeit.timeit("clamp(1, 5, 10)", "def clamp(val, minv, maxv): return minv if val < minv else maxv if val > maxv else val")
0.5956520039999305

Answer 3

Put them in a list, sort the list, chose middle element.

>>> def inbetween(minv,val,maxv):
...     return sorted([minv,val,maxv])[1]
... 
>>> inbetween(2,5,10)
5
>>> inbetween(2,1,10)
2
>>> inbetween(2,11,10)
10