[英]Navigating between 2 html pages in phonegap
I am working on phonegap application. 我正在研究phonegap应用程序。 I am facing one issue.
我正面临一个问题。
I have four html pages in my application. 我的应用程序中有四个html页面。 Every page contains some widgets like a button or a list view on click of button i move to next page.
每个页面包含一些小部件,例如按钮或单击按钮时的列表视图,然后移至下一页。 but when i want to come back on first page i can't.
但是当我想回到第一页时,我不能。 that is when I try to come back using back button of device it closes the app.
也就是说,当我尝试使用设备的后退按钮返回时,它会关闭该应用程序。
I am using device's back button and not user defined, so i need to handle that. 我正在使用设备的后退按钮,而不是用户定义的,因此我需要进行处理。 same as
onBackPressed();
与
onBackPressed();
相同onBackPressed();
in android. 在android中。
I know it is because of the WebView widget. 我知道是因为有WebView小部件。 but unable to find solution.
但找不到解决方案。
I am new to JavaScript, CSS, AJAX, jQuery and HTML5. 我是JavaScript,CSS,AJAX,jQuery和HTML5的新手。
How to handle back press in phonegap? 如何处理phonegap中的后按?
You can make a workaround to solve this problem. 您可以采取解决方法来解决此问题。
You can define a function to be triggered when back button is pressed and then verify which page your user is in, and depending on each page run a different action. 您可以定义当按下后退按钮时要触发的功能,然后验证用户所在的页面,并根据每个页面运行不同的操作。 For example, if he is in page3 then you go back to page 2, if page 2 then go back to page 1 and if he is in page1 you can close the application.
例如,如果他在第3页中,那么您将返回到第2页,如果第2页则返回到第1页,如果他在第1页中,则可以关闭该应用程序。
Wrote an example for you: 为您写一个例子:
<script type="text/javascript" charset="utf-8" src="phonegap-1.0.0.js"></script>
<script type="text/javascript" charset="utf-8">
document.addEventListener("deviceready", onDeviceReady, false);
// PhoneGap is loaded and it is now safe to make calls PhoneGap methods
function onDeviceReady() {
// Register the event listener
document.addEventListener("backbutton", onBackKeyDown, false);
}
// Handle the back button
function onBackKeyDown() {
var whichPage = functionToDetectCurrentPage(); //create a function or detect it somehow
switch(whichPage){
case "Page1":
//works only in android, iOS not quite sure, but heard it's not possible
//to do programatically
navigator.app.exitApp();
break;
case "Page2":
window.location = "Page1.html";
break;
case "Page3":
window.location = "Page2.html";
break;
case "Page4":
window.location = "Page2.html";
break;
}
}
Take a look at phonegap documention. 看看phonegap文档。 http://docs.phonegap.com/en/1.0.0/phonegap_events_events.md.html#backbutton
http://docs.phonegap.com/en/1.0.0/phonegap_events_events.md.html#backbutton
Let us know whether it helps you! 让我们知道它是否对您有帮助!
It may not be possible for an inbrowser
app. inbrowser
应用程序可能无法使用。
See related SO answer at: Handle Android Back Button on Phonegap InAppBrowser 在以下位置查看相关的SO答案: 处理Phonegap InAppBrowser上的Android后退按钮
You can use "backbutton" event for this. 您可以为此使用“后退按钮”事件。
Syntax : document.addEventListener("backbutton", yourCallbackFunction, false);
语法:
document.addEventListener("backbutton", yourCallbackFunction, false);
And you can write your "yourCallbackFunction" like this. 您可以这样编写“ yourCallbackFunction”。
function yourCallbackFunction(){ window.history.back(); }
Documentation link https://cordova.apache.org/docs/en/4.0.0/cordova/events/events.backbutton.html 文档链接https://cordova.apache.org/docs/en/4.0.0/cordova/events/events.backbutton.html
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