[英]Calculate the difference between two off64_t numbers C++
I would like to allocate memory in order to read (whole) very large files (15-25 Gb) in my C++ program. 我想分配内存,以便在我的C ++程序中读取(整个)非常大的文件(15-25 Gb)。 I have used
off64_t
type to get the beginning and ending positions of the file that I want to read, which are obtained from my file using function ftello64
. 我使用了
off64_t
类型来获取我想要读取的文件的开始和结束位置,这些文件是使用函数ftello64
从我的文件中ftello64
。 I would now like to get the difference between the two in a variable called size and then allocate this to a char array. 我现在想在一个名为size的变量中得到两者之间的差异,然后将其分配给char数组。 However, and despite compiling successfully, my code doesn't work properly.
但是,尽管编译成功,但我的代码无法正常工作。 I tried
size = (off64_t)(end_of_mem-start_of_mem);
我试过
size = (off64_t)(end_of_mem-start_of_mem);
where start_of_mem
and end_of_mem
are both off64_t
numbers but when I run my program the output is 其中
start_of_mem
和end_of_mem
都是off64_t
数字但是当我运行我的程序时输出是
Starting position in memory (start_of_mem):152757
Ending position in memory (end_of_mem):15808475159
Size: -1371546782
What variant type should I be using to get this right? 为了做到这一点,我应该使用哪种变体类型? Thanks in advance for your help and suggestions.
在此先感谢您的帮助和建议。
You are experiencing int down-casting from 64bit to 32bit side-effects. 您正在体验从64位到32位副作用的int。
Take a look at following experiment: 看看下面的实验:
#include <cstdint>
#include <iostream>
int main(){
int64_t int64 = 15808475159 - 152757;
int32_t int32 = int64;
std::cout << "int64_t: " << int64 << "\n";
std::cout << "int32_t: " << int32 << "\n";
}
Output: 输出:
int64_t: 15808322402
int32_t: -1371546782
Problem is the result of 15808475159 - 152757
is bigger than range of 32-bit integer. 问题是
15808475159 - 152757
的结果15808475159 - 152757
大于32位整数的范围。 Thus due overflow it gets truncated (or mod 2^32). 因此,由于溢出它被截断(或mod 2 ^ 32)。 Then because its declared as signed 32-bit it apparently falls into the a negative range of interpretation.
然后因为它被声明为带符号的32位,它显然属于负面的解释范围。
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