Flask-Frozen：如何生成404页面？

Question

I am trying to generate a 404 page for my Flask-Frozen application. Currently, this is my only error-handling logic in views.py

@app.errorhandler(404)
def page_not_found(e):
    return render_template('404.html'), 404

Apparently, that isn't enough code to do the trick, any suggestions?

Answer 1

There are two things you need to do:

1. Add a call to freezer.register_generator that returns at least one URL that will result in your 404 page:

    @freezer.register_generator def error_handlers(): yield "/404" 

2. Setup your web server to respond to 404 errors with your static page (the example is for Apache):

    ErrorDocument 404 /404.html 

Answer 2

You're using Frozen-Flask which freezes the site to serve it statically. There's no way to handle static pages in a static site unless you configure your webserver to serve a specific page in case of error.