如何获取我所有选择的数据并用while循环回显？ 只取一条记录

Question

$sqlWork = "SELECT * FROM work WHERE user_id = '$_SESSION[user_id]'";     
$resultWork = $connection->query($sqlWork);
$rowWork = $resultWork->fetch_assoc();

I currently have this table.

(I would add an image if I had the reputation)

http://imgur.com/fEYrzY0

This is how I am outputting my data.

    do {         
        echo "{$rowWork['work']}";     
    } while ($description = mysqli_fetch_array($resultWork));

Answer 1

use:

while($rowWork = $resultWork->fetch_assoc()){
        echo $rowWork['work'];     
}

I see that you are not using parametrized query, your code is vulnerable to SQL injection attack, you can avoid it by using prepared statement (parametrized)

Answer 2

$sqlWork = "SELECT * FROM work WHERE user_id = '$_SESSION[user_id]'";     
$resultWork = $connection->query($sqlWork);

while ($description = mysqli_fetch_array($resultWork)){
echo $description['work'];
}

Answer 3

You can also do this based on these:

foreach

Use when iterating through an array whose length is (or can be) unknown.

for

Use when iterating through an array whose length is set, or, when you need a counter.

while

Use when you're iterating through an array with the express purpose of finding, or triggering a certain flag.