在OpenCV和C＃上获取RGB颜色值

Question

I can't find a solution to a simple problem I have:

In this code:

private void ibOriginal_MouseClick(object sender, MouseEventArgs e)
{
    int mouse_get_X = (int)(e.Location.X);
    int mouse_get_Y = (int)(e.Location.Y);

    Byte byte_color = imgOriginal.Data[mouse_get_X, mouse_get_Y, 0];
}

I want to have an RGB value (in a 3-dimensional array of int) of a pixel with X,Y coordinates get by a Mouse Click.

Can I make a conversion of "byte_color"? Is it correct?

I can't find anything in C# that can help me, I'm using EmguCV.

Answer 1

First of all, you'll probably want to have:

imgOriginal.Data[mouse_get_Y, mouse_get_X, 0];  //note X and Y swapped

Secondly, in OpenCV data is stored in bands which you choose with the last index. Their interpretation depends on your image type. If you have BGR image type for example, then:

imgOriginal.Data[mouse_get_Y, mouse_get_X, 0]; // blue
imgOriginal.Data[mouse_get_Y, mouse_get_X, 1]; // green
imgOriginal.Data[mouse_get_Y, mouse_get_X, 2]; // red

Similarly to other image types defined in this namespace: http://www.emgu.com/wiki/files/1.3.0.0/html/b72c032d-59ae-c36f-5e00-12f8d621dfb8.htm

When bands have byte resolution they have values from range 0...255, so basically you have an integer already, and you can put it into a text box easily:

textBox.Text = byteValue.ToString();