[英]Split a string into array without empty element
Attempting to split a string into separated letters 尝试将字符串拆分为多个字母
String string1 ="KKXGJRNQGA";
List<String> solutionArray = Arrays.asList(string1.split(""));
will return [, K, K, X, G, J, R, N, Q, G, A]
before each alphabet a space and at [0] is an empty element. 将在每个字母前加一个空格,并且在[0]处为空元素
[, K, K, X, G, J, R, N, Q, G, A]
将返回[, K, K, X, G, J, R, N, Q, G, A]
。
But actually i want is [K,K,X,G,J,R,N,Q,G,A]
, is there a way to solve it? 但实际上我要的是
[K,K,X,G,J,R,N,Q,G,A]
,有没有办法解决呢? can using regex match? 可以使用正则表达式匹配吗?
Using string1.split("")
will return an empty first value. 使用
string1.split("")
将返回一个空的第一个值。
Use toCharArray() which converts the string to a new character array. 使用toCharArray()将字符串转换为新的字符数组。
"KKXGJRNQGA".toCharArray()
or a simple regular expression 或简单的正则表达式
String s = "KKXGJRNQGA";
String[] p = s.split("(?!^)");
System.out.println(Arrays.asList(p));
Output: 输出:
[K, K, X, G, J, R, N, Q, G, A]
怎么样
char[] letters = string1.toCharArray();
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