preg_match_all在两个句子之间

Question

from the phrase:

 <div class="latestf"> <a href="http://www.x.ro/anamaria/"
 rel="nofollow"

I want to extract anamaria. How to do that with preg_match_all ?

I tried:

preg_match_all("'<div class=\"latestf\">
<a href=\"http://www.x.ro/(.*?)\" rel=\"nofollow\"'si", $source, $match);

but it didn`t work...

Thank you in advance !

Answer 1

Try this:

$source = '<div class="latestf"> <a href="http://www.x.ro/anamaria/" rel="nofollow"';


preg_match_all('#<div\s*class="latestf">\s*<a\s*href="http://www\.x\.ro/(.*?)/?"\s*rel="nofollow"#i', $source, $match);

print_r($match);

Array
(
    [0] => Array
        (
            [0] => <div class="latestf"> <a href="http://www.x.ro/anamaria/" rel="nofollow"
        )

    [1] => Array
        (
            [0] => anamaria
        )

)

Answer 2

Don't try to parse HTML with regex. Use a DOM parser instead:

$html = '<div class="latestf"> <a href="http://www.x.ro/anamaria/"
 rel="nofollow"';

$dom = new DOMDocument;
@$dom->loadHTML($html);
foreach ($dom->getElementsByTagName('a') as $node)
{
    $link = $node->getAttribute("href");
}

$parsed = parse_url($link);

echo substr($parsed['path'], 1, -1);

Output:

anamaria

Demo!

Answer 3

/ should be escaped like this \\/

<?php

  $source = '<div class="latestf"> <a href="http://www.x.ro/anamaria/" rel="nofollow"';

  preg_match_all('/<div class="latestf"> <a href="http:\/\/www.x.ro\/(.*?)\/" rel="nofollow"/', $source, $match);

  var_dump($match);exit;