[英]PHP search and replace regex pattern
I'm trying to get a string which matches by a regex pattern ( {$ ... } ). 我正在尝试获取由正则表达式模式({$ ...})匹配的字符串。 But I don't want the brackets and the $ sign returned.
但是我不希望括号和$符号返回。
For example 例如
{$Testpath}/Testlink
should return 应该回来
Testpath
My regex pattern looks like this at the moment: 目前,我的正则表达式模式如下所示:
^{\$.*}$
Try the following regex: 尝试以下正则表达式:
^\{\$\K[^}]*(?=\})
This expression mathces start-of-string ^
then a literal {
then a literal $
then it ignores those using \\K
anchor, then it matches one or more characters which aren't a }
then it looks ahead (?=\\})
for a literal }
. 该表达式先计算字符串的开头
^
然后是文字{
然后是文字$
然后忽略使用\\K
锚的字符,然后匹配一个或多个不是}
字符,然后向前看(?=\\})
文字}
。
You may not need the end-of-line anchor $
because the text you are trying to match might not end at the end of the string and you may not need the start-of-line ^
anchor for the opposite reason, that is the pattern you are trying to match may not be at the start of the string or line. 您可能不需要行末锚
$
因为您要匹配的文本可能不会在字符串的末尾结束,并且由于相反的原因,您可能不需要行起始^
锚,即您尝试匹配的模式可能不在字符串或行的开头。
I think you should remove ^
and $
and use the global modifier. 我认为您应该删除
^
和$
并使用global修饰符。
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