C-将元素从结构内部传递到功能

Question

I have a structure comprised of an array of pointers to other structures of a different type.

    typedef struct{
        NodeT* nodes[2];
        int size; 
    }stackT; 

with:

    typedef struct{
        char info; 
    }NodeT;

And I have a pointer to the above (first) structure:

    stackT* stackPtr;

Assuming the memory is allocated for the stackT structure as well as both NodeT structures with associated assignments for the members of both NodeT structures, how would I pass to a function one of the pointers in stackT?

---

For example:

    void setChar(NodeT* nodePtr, char setTo){
        nodePtr->info = setTo;
    }

called with line:

    setChar(stackPtr->nodes[0], 'A');

Does not work. I figured it had something to do with the -> syntax dereferencing the pointer whereby I am actually passing in a structure. I do not get any compilation errors, but when I check for the assignment by printing whatever is stored in char info I do not get anything.

Is the notation incorrect or do I have issues elsewhere in the program perhaps? I just wanted to rule this out first (proper passing syntax).

Answer 1

If someone is looking for a solution to this problem, the above code was actually correct. Assuming you have an array of pointer in some structure and you wish to pass such a pointer, the correct syntax would be:

someFunc( structPtr->ptrArray[0] )

The line:

structPtr->ptrArray[0]

Actually returns a pointer, and not whatever the pointer is pointer to.

(*structPtr).ptrArray[0]

Is also equivalent.

That being said, I either mistakenly interpreted the information before me, or I had underlying errors elsewhere in the my code.