SQL查询-如何同时使用存在和不存在条件

Question

I have two tables TableA and TableB . TableA has a column newValue and oldValue . TableB has a column value .

I want the following result: get all the rows from TableA where newValue exist in TableB and oldValue not exist in TableB .

Both tables has many rows so performance is important!

How would you accomplish that in SQL Server 2010/2012?

(ui: I found no property title for this question).

Edit:

The first thing I tried is:

SELECT newValue, oldValue
FROM TableA
WHERE newValue IN (SELECT value FROM TableB) 
  AND oldValue NOT IN (SELECT value FROM Table B)

But this is inefficient and has poor performance on my database. I'm looking for other solutions.

Answer 1

I think avoiding EXISTS and IN helps with speed here:

SELECT
        *
    FROM TableA
    WHERE
        (SELECT TOP 1 1 FROM TableB WHERE value = newValue) IS NOT NULL
        AND
        (SELECT TOP 1 1 FROM TableB WHERE value = oldValue) IS NULL

Answer 2

You can exists use exists/not exists

SELECT newValue, oldValue
FROM TableA as t1 
where exists(SELECT value FROM TableB as t2 where t1.newValue=t2.value) and 
 not exists(SELECT value FROM TableB as t3 where t1.olvalue=t3.value)

Answer 3

If you have indexes on value , newvalue and oldvalue , you can try this:

select
    a.newValue, a.oldValue
from TableA as a
where
    a.newValue in (select distinct b.value from TableB as b) and
    a.oldValue not in (select distinct b.value from TableB as b)

or exists :

select
    a.newValue, a.oldValue
from TableA as a
where
    exists (select * from TableB as b where b.value = a.newValue) and
    not exists (select * from TableB as b where b.value = a.oldValue)

Answer 4

Select Distinct A.*
From TableA A
     Inner Join TableB B on A.newValue = B.Value
Where A.OldValue NOT In (Select Value From TableB)

Answer 5

Please try:

select * from TableA where newValue in (select value from TableB)
union
select * from TableA where oldValue not in (select value from TableB)

Answer 6

You can do it with single exist condition.

 SELECT newValue, oldValue
 FROM TableA a
 WHERE exists 
 (
  SELECT 1 FROM TableB b 
  where a.newValue = b.value 
  and a.oldValue != b.value)