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System.linq-GroupBy和Max

[英]System.linq - GroupBy and Max

How do I combine groupBy and max? 如何结合groupBy和max? I want to group by name and get only the latest version. 我想按名称分组并仅获取最新版本。 Something like this 像这样

Docs.GroupBy(x => x.Name ).Max(x => x.VersionNumber)

Is it possible? 可能吗?

the following 下列

searchResult.Docs.GroupBy(x => x.PackageName).Select(x => x.Max(x => x.VersionNumber));

returns a 返回一个

 IEnumerable<int> 

and not 并不是

 IEnumerable<Doc> 

Order each group by version number and select first doc only (it will have max version number): 按版本号订购每个组,然后仅选择第一个文档(它将具有最大版本号):

Docs.GroupBy(x => x.Name)
    .Select(g => g.OrderByDescending(x => x.VersionNumber).First())

Your code is not working, because you are selecting value of max version number (which is int) instead of selecting doc which has max version number. 您的代码不起作用,因为您选择的是最大版本号(int),而不是选择具有最大版本号的doc。

您可以对其进行排序,并获得结果的第一个元素,例如:

searchResult.Docs.GroupBy(x => x.PackageName).OrderByDescending(x => x.Max(x => x.VersionNumber)).FirstOrDefault();

为了获取组的最新元素,查询是:

.GroupBy(x=>x.Name).Select(y=>y.OrderbyDescending(z=>z.Version).FirstorDefault());

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