[英]System.linq - GroupBy and Max
How do I combine groupBy and max? 如何结合groupBy和max? I want to group by name and get only the latest version.
我想按名称分组并仅获取最新版本。 Something like this
像这样
Docs.GroupBy(x => x.Name ).Max(x => x.VersionNumber)
Is it possible? 可能吗?
the following 下列
searchResult.Docs.GroupBy(x => x.PackageName).Select(x => x.Max(x => x.VersionNumber));
returns a 返回一个
IEnumerable<int>
and not 并不是
IEnumerable<Doc>
Order each group by version number and select first doc only (it will have max version number): 按版本号订购每个组,然后仅选择第一个文档(它将具有最大版本号):
Docs.GroupBy(x => x.Name)
.Select(g => g.OrderByDescending(x => x.VersionNumber).First())
Your code is not working, because you are selecting value of max version number (which is int) instead of selecting doc which has max version number. 您的代码不起作用,因为您选择的是最大版本号(int),而不是选择具有最大版本号的doc。
您可以对其进行排序,并获得结果的第一个元素,例如:
searchResult.Docs.GroupBy(x => x.PackageName).OrderByDescending(x => x.Max(x => x.VersionNumber)).FirstOrDefault();
为了获取组的最新元素,查询是:
.GroupBy(x=>x.Name).Select(y=>y.OrderbyDescending(z=>z.Version).FirstorDefault());
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