[英]Mixing enumeration in switch-case
What does C standard talk about mixing enumerations in the case constants of a switch
- case
statement? 什么C标准谈的情况下常数混合枚举
switch
- case
说法? I ensure that there are no duplicate values of the mixed enum
types. 我确保混合
enum
类型没有重复的值。
switch (value) /* value is int type */
{
case enum1_val: /* enum1_val is of enum type enum1 */
break;
case enum2_val: /* enum2_val is of enum type enum2 */
break;
}
I get the code compiled clean with the -ansi -Wall
flags, but Klockwork reports some problem in this code. 我使用
-ansi -Wall
标志将代码编译干净,但是Klockwork在此代码中报告了一些问题。
It's allowed in C. What you get is a warning by Klocwork because it thinks mixing different enum
types is not a good idea. 它在C中是允许的。您得到的是Klocwork的警告,因为它认为混合不同的
enum
类型不是一个好主意。 (I personally agree on this): (我个人对此表示同意):
Quoting from Klocwork : 从Klocwork报价:
Inconsistent case labels
案例标签不一致
The INCONSISTENT.LABEL checker finds situations in which more than one enum type is used as a switch expression or as a label in a switch statement.
INCONSISTENT.LABEL检查器可查找将多个枚举类型用作switch表达式或switch语句中的标签的情况。
Vulnerability and risk
脆弱性和风险
Using labels with different enum types in a switch statement can cause problems because enum members with the same value can have different meanings.
在switch语句中使用具有不同枚举类型的标签可能会引起问题,因为具有相同值的枚举成员可能具有不同的含义。 The design intent fails, and unexpected results can occur.
设计意图失败,并且可能发生意外结果。
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