简体   繁体   English

如何断言大于使用 JUnit 断言?

[英]How to assert greater than using JUnit Assert?

I have these values coming from a test我有这些值来自测试

previousTokenValues[1] = "1378994409108"
currentTokenValues[1] = "1378994416509"

and I try我尝试

    // current timestamp is greater
    assertTrue(Long.parseLong(previousTokenValues[1]) > Long.parseLong(currentTokenValues[1]));

I get the java.lang.AssertionError and detailMessage on debugging is null .我在调试时得到java.lang.AssertionErrordetailMessagenull

How can I assert greater than conditions in using JUnit如何在使用JUnit断言大于条件

Just how you've done it.只是你是如何做到的。 assertTrue(boolean) also has an overload assertTrue(String, boolean) where the String is the message in case of failure; assertTrue(boolean)也有一个重载assertTrue(String, boolean) ,其中String是失败时的消息; you can use that if you want to print that such-and-such wasn't greater than so-and-so.如果你想打印某某不大于某某,你可以使用它。

You could also add hamcrest-all as a dependency to use matchers.您还可以添加hamcrest-all作为使用匹配器的依赖项。 See https://code.google.com/p/hamcrest/wiki/Tutorial :请参阅https://code.google.com/p/hamcrest/wiki/Tutorial

import static org.hamcrest.MatcherAssert.assertThat;
import static org.hamcrest.Matchers.*;

assertThat("timestamp",
           Long.parseLong(previousTokenValues[1]),
           greaterThan(Long.parseLong(currentTokenValues[1])));

That gives an error like:这给出了一个错误,如:

java.lang.AssertionError: timestamp
Expected: a value greater than <456L>
     but: <123L> was less than <456L>

When using JUnit asserts, I always make the message nice and clear.使用 JUnit 断言时,我总是使消息清晰明了。 It saves huge amounts of time debugging.它节省了大量的调试时间。 Doing it this way avoids having to add a added dependency on hamcrest Matchers.这样做可以避免添加对 hamcrest Matchers 的额外依赖。

previousTokenValues[1] = "1378994409108";
currentTokenValues[1] = "1378994416509";

Long prev = Long.parseLong(previousTokenValues[1]);
Long curr = Long.parseLong(currentTokenValues[1]);
assertTrue("Previous (" + prev + ") should be greater than current (" + curr + ")", prev > curr);

you can also try below simple soln:您也可以尝试以下简单的解决方案:

previousTokenValues[1] = "1378994409108";
currentTokenValues[1] = "1378994416509";

Long prev = Long.parseLong(previousTokenValues[1]);
Long curr = Long.parseLong(currentTokenValues[1]);

Assert.assertTrue(prev  > curr );   

You should add Hamcrest-library to your Build Path.您应该将 Hamcrest-library 添加到您的构建路径中。 It contains the needed Matchers.class which has the lessThan() method.它包含所需的 Matchers.class,它具有 lessThan() 方法。

Dependency as below.依赖如下。

<dependency>
  <groupId>org.hamcrest</groupId>
  <artifactId>hamcrest-library</artifactId>
  <version>1.3</version>
  <scope>test</scope>
</dependency>

Alternatively if adding extra library such as hamcrest is not desirable, the logic can be implemented as utility method using junit dependency only:或者,如果不希望添加额外的库,例如hamcrest ,则可以将逻辑实现为仅使用junit依赖项的实用程序方法:

public static void assertGreaterThan(int greater, int lesser) {
    assertGreaterThan(greater, lesser, null);
}

public static void assertGreaterThan(int greater, int lesser, String message) {
    if (greater <= lesser) {
        fail((StringUtils.isNotBlank(message) ? message + " ==> " : "") +
                "Expected: a value greater than <" + lesser + ">\n" +
                "But <" + greater + "> was " + (greater == lesser ? "equal to" : "less than") + " <" + lesser + ">");
    }
}
assertTrue("your message", previousTokenValues[1].compareTo(currentTokenValues[1]) > 0)

这通过前 > 当前值

As I recognize, at the moment, in JUnit, the syntax is like this:据我所知,目前在 JUnit 中,语法是这样的:

AssertTrue(Long.parseLong(previousTokenValues[1]) > Long.parseLong(currentTokenValues[1]), "your fail message ");

Means that, the condition is in front of the message.意思是,条件在消息前面。

你可以这样说

  assertTrue("your fail message ",Long.parseLong(previousTokenValues[1]) > Long.parseLong(currentTokenValues[1]));

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM