[英]Datatables Jquery error in console
Uncaught TypeError: Object [object Object] has no method 'fnFilter' 未捕获的TypeError:对象[object Object]没有方法'fnFilter'
$(document).ready(function () {
var selectedColumn = $('#columnlist').find(":selected").text();
$('#csearchtext').bind("change paste keyup", function () {
var input = $('#csearchtext').val();
console.log(input);
$('#table_id').fnFilter('',4);
});
$('#dblist').on('change', function () {
var selected = $('#dblist').find(":selected").text();
tablefill(selected);
});
$('#search').click(function () {
var selected = $('#dblist').find(":selected").text();
tablefill(selected);
});
function tablefill(selected) {
$('.advsearchbar').show();
$('#stable').show();
$('#table_id').dataTable({
"sAjaxSource": '/php/connect/searchtablequery.php',
"bProcessing": true,
"sScrollY": "500px",
"bDeferRender": true,
"bDestroy": true,
"sAjaxDataProp": "",
"fnServerParams": function (aoData) {
aoData.push({ "name": "db", "value": selected });
},
"aoColumns": [
{ "mData": "calldate" },
{ "mData": "recordingfile" },
{ "mData": "uniqueid" },
{ "mData": "src" },
{ "mData": "did" },
{ "mData": "lastapp" },
{ "mData": "dst" },
{ "mData": "disposition" },
{ "mData": "duration" },
{ "mData": "userfield" },
{ "mData": "accountcode"}],
"iDisplayLength": 20,
"bJQueryUI": true,
"sPaginationType": "full_numbers",
"sDom": '<"H"Tfr>t<"F"ip>',
"oTableTools": {
"sSwfPath": "/DataTables/extras/TableTools/media/swf/copy_csv_xls_pdf.swf",
"aButtons": [
"copy", "csv", "xls", "pdf",
{
"sExtends": "collection",
"sButtonText": "Save",
"aButtons": ["csv", "xls", "pdf"]
}]
}
});
}
}); });
Uncaught TypeError: Object [object Object] has no method 'fnFilter' I am not sure why this is happening the jquery is included because the datatable is being created just fine. 未被捕获的TypeError:对象[object Object]没有方法'fnFilter'我不确定为什么会发生这种情况,因为创建了数据表就很好了,所以要包含jquery。 Any help on this will be great.
任何帮助都会很大。
您必须像这样链接dataTable对象。
$('#table_id').dataTable().fnFilter('', 4);
You need to get the dataTable object, instead of the jQuery object. 您需要获取dataTable对象,而不是jQuery对象。
$('#table_id').dataTable().fnFilter('',4);
From the docs: 从文档:
$(document).ready(function() {
var oTable = $('#example').dataTable();
// Sometime later - filter...
oTable.fnFilter( 'test string' );
} );
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