Javascript闭包（使用参数名称在同一函数中定义对象）

Question

I have the below code. Need to know how "a" is used as a function parameter, and then inside the same function it again used as object "a" to call another function.And what is mean by "a || {}" at the end of code.

E.martin= function (a) {
a = mergein({ api_url: "/somefolder/",
          json_parameter: false,
          channel_id: null,
          after_response_hook: null},
          a || {});

Answer 1

//Here 'a' is a function arg
E.martin= function (a) {

//Here 'a' is overwritten by the returned value from mergein
a = mergein({ api_url: "/somefolder/",
      json_parameter: false,
      channel_id: null,
      after_response_hook: null},

      //Here 'a' is send to the function, if it's not null/false.
      //if 'a' is null/false an empty object will be created and sent instead.
      a || {});

mergein does probably add a function to the arg a .

Answer 2

I can answer the a || {}; section

This is a way to check if "a" already exists. If it does then use it, if it doesnt the create it as a new object.

Answer 3

EDIT :

To answer your actual question (I originally thought you were having issues with the code), the a || {} a || {} part of the code says "either use 'a' or if 'a' is not defined then use a new empty object ({})".

ADVICE :

I would advise you return the a in your E.martin method as objects in JavaScript are not hard referenced. If you don't return the result, you'll likely lose the original object that you sent to the method.

Let's say mergein is a method that concatenates two objects:

function mergein(new_obj, old_obj){

    for(var i in new_obj){

        old_obj[i] = new_obj[i];   

    }

    return old_obj;

}

If we have your original method, we will lose our original object keys/values when we get our result back:

E.martin = function (a) {

    a = mergein({ api_url: "/somefolder/",
          json_parameter: false,
          channel_id: null,
          after_response_hook: null},
          a || {});

}

var b = {foo:'bar'};

var result = martin(b);

console.log(result['foo']); // error

If we return our a object, we'll get back our original object with the added keys/values:

E.martin = function (a) {

    return mergein({ api_url: "/somefolder/",
          json_parameter: false,
          channel_id: null,
          after_response_hook: null},
          a || {});

}

var b = {foo:'bar'};

var result = martin(b);

console.log(result['foo']); // 'bar'