[英]string.split() and dealing with duplicates
I have a string String test = "-b--b--";
我有一个字符串
String test = "-b--b--";
I want an array that has {"", "b", "", "b", ""}
我想要一个具有
{"", "b", "", "b", ""}
的数组
How can I call the string.split()
function to obtain this? 如何调用
string.split()
函数来获取此信息?
EDIT: 编辑:
I've tried test.split("-")
. 我已经尝试过
test.split("-")
。 My tests gave me {"", "b", "", "b"}
. 我的测试给了我
{"", "b", "", "b"}
。 Why does the method not include the last emptyspace on my array if it did include the first one between the first pair of hyphens? 如果该方法在第一对连字符之间包含第一个空格,为什么该方法不包括数组中的最后一个空格?
Basically I want to get all the characters between the hypens, where String test = ---
should give me {"", "", ""}
基本上我想得到连字符之间的所有字符,其中
String test = ---
应该给我{"", "", ""}
Its mentioned in the docs 它在文档中提到
Trailing empty strings not included in the resulting array.
结果数组中不包含结尾的空字符串。
For the desired result change it to 为了获得所需的结果,将其更改为
test.split("-",Integer.MAX_VALUE);
This would consider empty strings and so the output would be 这将考虑空字符串,因此输出将是
"", "b", "", "b", "" , ""
you can try .getCharAt()
method of string to your problem. 您可以尝试字符串的
.getCharAt()
方法解决您的问题。
The following code can help: 以下代码可以帮助您:
char test1[]=new char[test.length()];
for(int i=0;i<test.length();i++)
if(test.getCharAt(i)=='-')
test1[i]=' ';
else
test[i]=test.getCharAt(i);
hope this will help you.... 希望这个能对您有所帮助....
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