TypeError：“ __ init __（）为关键字参数'name'获得了多个值”

Question

Why am I getting the error in the title when I call this constructor?

I call User(**args) with the following dictionary as args :

{'name': u'Rose Perrone', 'ipAddress': '127.0.0.1', 'email': u'hi@gmail.com'}

This is the constructor:

def __init__(name,
             ipAddress,
             password=None,
             email=None,
             deleted=None,
             includePromoted=None,
             explicit=None):

Answer 1

Firstly, make your first parameter self . You don't have to, but it is very, very common, and when someone is reading your code (like right now), it's annoying :p.

name is acting like self here. You aren't supposed to pass a value for name (self), because python already does that. However, you are doing this, because you have a key name in your dictionary. Thus, you're passing two things to one parameter, hence the error.

To fix this:

1. Firstly, self !!!!

2. But also don't forget to add in your name parameter.

So altogether:

args = {'name': u'Rose Perrone', 'ipAddress': '127.0.0.1', 'email': u'hi@gmail.com'}
class MyClass:
    def __init__(self,
                 name,
                 ipAddress,
                 password=None,
                 email=None,
                 deleted=None,
                 includePromoted=None,
                 explicit=None):
                pass

MyClass(**args)
# <__main__.MyClass instance at blah>