[英]Compare two tables from MYSQL
I have to compare two tables , then list all of them as check boxes, while matched values should be checked and non matching without checked 我必须比较两个表,然后将所有表都列为复选框,同时应检查匹配的值,不检查则不匹配
//table 1 //表格1
rid| role_name
1 | school
2 | college
3 | University
//table2 // table2
id|rid | category
1 | 1 | uniform
2 | 2 | uniform
match rid from both table where category = 'uniform' list all and checked the matching rid 从category ='uniform'全部列出的两个表中匹配掉,并检查匹配掉
$query = "select a.* from table1 a, table b where a.rid = b.rid and a.category = b.category";
$result = mysqli->query($query);
$fetched = $result->fetch_assoc();
foreach($fetched as $row){
echo "<input type='checkbox' name='{$row['rid']}' value='' checked > {$row['category']}";
}
$query = "select t1.rid, 'matched' as matching from table1 t1 where t1.rid in (
select rid from table2 where category = 'uniform')
union
select t1.rid ,'notmatched' from table1 t1 where t1.rid not in (
select rid from table2 where category = 'uniform')";
$result = mysqli->query($query);
$fetched = $result->fetch_assoc();
foreach($fetched as $row){
if($row['matching'] = 'matched'){
echo "<input type='checkbox' name='{$row['rid']}' value='' checked='checked' >"; }
else{
echo "<input type='checkbox' name='{$row['rid']}' value='' >"; }
}
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