[英]Query to select duplicates in column 2 based on column 1 in MySQL
Let's say I have two columns: id and date. 假设我有两列:id和date。
I want to give it an id and it'll find all the duplicates of the value date of the column id. 我想给它一个ID,它将找到列ID的起息日的所有重复项。
Example: 例:
id |date
1 |2013-09-16
2 |2013-09-16
3 |2013-09-23
4 |2013-09-23
I want to give it id 1 (without giving anything about date) and it'll give me a table of 2 columns listing the duplicates of id 1's date 我想给它id 1(不提供任何有关日期的信息),它会给我一个2列的表格,列出id 1的日期的重复项
Thanks in advance! 提前致谢!
select * from your_table
where `date` in
(
select `date`
from your_table
where id = 1
)
or if you like to use a join 或者如果您想使用联接
select t.*
from your_table t
inner join
(
select `date`
from your_table
where id = 1
) x on x.date = t.date
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