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在Symfony2中使用OAuth 1类

[英]Use OAuth 1 Class in Symfony2

Hi I want to integrate the Yahoo BOSS API with Symfony2, but the OAuth code class suggested by Yahoo doesn't seem to work with modern PHP frameworks. 嗨,我想将Yahoo BOSS API与Symfony2集成,但是Yahoo建议的OAuth代码类似乎不适用于现代PHP框架。

http://oauth.googlecode.com/svn/code/php/OAuth.php http://oauth.googlecode.com/svn/code/php/OAuth.php

/* Generic exception class
 */
class OAuthException extends Exception {
  // pass
}

class OAuthConsumer {
  public $key;
  public $secret;

  function __construct($key, $secret, $callback_url=NULL) {
    $this->key = $key;
    $this->secret = $secret;
    $this->callback_url = $callback_url;
  }

  function __toString() {
    return "OAuthConsumer[key=$this->key,secret=$this->secret]";
  }
} [...]

http://developer.yahoo.com/boss/search/boss_api_guide/codeexamples.html#oauth_php http://developer.yahoo.com/boss/search/boss_api_guide/codeexamples.html#oauth_php

I think the OAuth class has namespace issues, what steps do I need to take to implement this class in Symfony2? 我认为OAuth类存在名称空间问题,在Symfony2中实现该类需要采取哪些步骤?

1) Create a directory like Project/src/ OAuth 1)创建一个目录,例如Project / src / OAuth

2) Place the classes in separate files inside that directory. 2)将类放在该目录内的单独文件中。

3) Add namespace OAuth; 3)添加namespace OAuth; at the beginning of every OAuth class. 在每个OAuth类的开头。

4) Add a backslash to the Exception class (or add use Exception; ): 4)在Exception类中添加一个反斜杠(或添加use Exception; ):

class OAuthException extends \Exception

5) Avoid underscores in class names ( Laravel-Oauth2 Issue in Laravel 4 , Underscores in Namespaces and Class Names ): 5)避免在类名中使用下划线( Laravel 4中的Laravel-Oauth2问题在名称空间和类名中使用下划线 ):

abstract class OAuthSignatureMethodRSASHA1 extends OAuthSignatureMethod

class OAuthSignatureMethodPLAINTEXT extends OAuthSignatureMethod

class OAuthSignatureMethodHMACSHA1 extends OAuthSignatureMethod

6) Fix the array_map call in OAuthUtil: 6)修复OAuthUtil中的array_map调用:

return array_map(array('OAuth\OAuthUtil', 'urlencode_rfc3986'), $input);

7) And finally use it: 7)最后使用它:

<?php

namespace My\PlaygroundBundle\Controller;

use Symfony\Bundle\FrameworkBundle\Controller\Controller;
use Sensio\Bundle\FrameworkExtraBundle\Configuration\Route;
use Sensio\Bundle\FrameworkExtraBundle\Configuration\Template;

use OAuth\OAuthConsumer;
use OAuth\OAuthRequest;
use OAuth\OAuthSignatureMethodHMACSHA1;
use OAuth\OAuthUtil;

class DefaultController extends Controller
{
    /**
     * @Route("/")
     * @Template()
     */
    public function indexAction()
    {
        $cc_key  = "your consumer key here";
        $cc_secret = "your consumer secret here";
        $url = "http://yboss.yahooapis.com/ysearch/news,web,images";
        $args = array();
        $args["q"] = "yahoo";
        $args["format"] = "json";

        $consumer = new OAuthConsumer($cc_key, $cc_secret);
        $request = OAuthRequest::from_consumer_and_token($consumer, NULL,"GET", $url, $args);
        $request->sign_request(new OAuthSignatureMethodHMACSHA1(), $consumer, NULL);
        $url = sprintf("%s?%s", $url, OAuthUtil::build_http_query($args));
        $ch = curl_init();
        $headers = array($request->to_header());
        curl_setopt($ch, CURLOPT_HTTPHEADER, $headers);
        curl_setopt($ch, CURLOPT_URL, $url);
        curl_setopt($ch, CURLOPT_RETURNTRANSFER, TRUE);
        $rsp = curl_exec($ch);
        $results = json_decode($rsp);

        return array(
            'results' => $results
        );
    }
}

So those are the steps I followed and it worked; 这些就是我所遵循的步骤,而且确实有效。 you can grab the classes from here: https://github.com/coma/OAuthSOSample 您可以从这里获取课程: https : //github.com/coma/OAuthSOSample

In Symfony 2 I can recommend a third party bundle that will support OAuth 1 & 2. 在Symfony 2中,我可以推荐一个支持OAuth 1和2的第三方捆绑软件。

Take at look: https://github.com/hwi/HWIOAuthBundle 看一下: https : //github.com/hwi/HWIOAuthBundle

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