Python：为列表中的每个对象修改一个属性

Question

My question is basic and is maybe a duplicate but I haven't found the answer.

I am looking for the most efficient (pythonic) way of adding 1 to the attribute x of all objects of a given list.

class Any(object):
   def __init__(self, x):
       self.x = x

l = [Any(1), Any(-3), Any(1), Any(4), Any(6), Any(7), Any(3)]

Is there a better solution than (using list comprehension for example):

for i in l:
    i.x += 1

Answer 1

Nothing wrong with your code, but if you want to use it in a comprehension, add an "increment" method:

def inc(self, amount=1):
    self.x += amount
    return self

Answer 2

您的方式完全是pythonic。