将列表转换为dict，列表项作为键，列表索引作为python中的值

Question

I want to transform

l = ['a','b','c','d']

to

d = {'a': 0, 'b': 1, 'c': 2, 'd': 3}

The best solution I have so far is that one:

d = {l[i]:i for i in range(len(l))}

Is there more elegant way to do this?

Answer 1

d = {e:i for i, e in enumerate(l)}

编辑：正如@LeonYoung建议的那样，如果你想与python <2.7兼容（尽管有标签），你必须使用

d = dict((e, i) for i, e in enumerate(l))

Answer 2

With itertools , just for fun

>>> from itertools import count, izip
>>> L = ['a', 'b', 'c', 'd']
>>> dict(izip(L, count()))
{'a': 0, 'c': 2, 'b': 1, 'd': 3}