[英]Replacing special chars in a string with a single unique char
I have a string like so: 我有一个像这样的字符串:
string inputStr = "Name*&^%LastName*#@";
The following Regex will replace all the special chars with a '-' 以下正则表达式将所有特殊字符替换为“-”
Regex rgx = new Regex("[^a-zA-Z0-9 - _]");
someStr = rgx.Replace(someStr, "-");
That produces an output something like: Name---LastName--- 产生的输出类似:Name --- LastName ---
How do I replace '---' with a single '-' so the output looks like this: 如何用单个“-”替换“ ---”,因此输出如下所示:
Name-LastName
So the question is how do I replace all the special chars with a single '-'? 因此,问题是如何将所有特殊字符替换为单个“-”?
Regards. 问候。
Try this 尝试这个
Regex rgx = new Regex("[^a-zA-Z0-9 \- _]+");//note - character is escaped
or 要么
Regex rgx = new Regex("[^a-zA-Z0-9 _-]+");//or use - as last character
But this will give Name-LastName-
Is this okay or..? 但这将给出
Name-LastName-
可以吗?
If you don't need -
at last position you can use the following code as well. 如果不需要
-
在最后的位置,您也可以使用以下代码。 Credit goes to @MatthewStrawbridge. 归功于@MatthewStrawbridge。 You can see in comments.
您可以在评论中看到。
string someStr = rgx.Replace(inputStr, "-").TrimEnd('-');
will output Name-LastName
. 将输出
Name-LastName
。
Edit: As @pguardiario pointed in comments updated my answer to escape -
since range( []
) has special meaning for -
character. 编辑:正如@pguardiario在评论中指出的那样,更新了我的转义答案
-
因为range( []
)对于-
字符具有特殊含义。 If we need -
as a literal we need to escape it or make it first or last character of the character class in order to behave as literal. 如果需要
-
作为文字,我们需要对其进行转义或使其成为字符类的第一个或最后一个字符,以使其表现为文字。
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