从当前月份开始的月份中打印3年日历

Question

I am getting the current date in javascript and then I convert it to the current month. Based on the current month (9 now), I want to print the month calendar for the last 3 years backwards. So, if we have September 2013, the following has to be printed:

08 09 10 11 12 2010
01 02 03 04 05 06 07 08 09 10 11 12 2011

01 02 03 04 05 06 07 08 09 10 11 12 2012

01 02 03 04 05 06 07 08 2013

I have a general idea how to print the first line, but I'm struggling how to print the rest of the calendar. Here is my code for the first line (2013):

function printCalendarRows(){
        var d = new Date();
        var n = (d.getMonth()) + 1;
        var twelve = 12;
        for(var i = n; i <= 12; i++){
            for(var j = 12; j >= n; j--){
                console.log(i);
                console.log(j);
            }
        }
}    

Any recommendations? Thanks

Answer 1

function calRows() {
    var date,
        now = new Date(),
        str = "";

    for (var i = -37;i++;) {       
        date = new Date(now.getFullYear(), now.getMonth() + i - 1, 1)
        month = ("0" + (date.getMonth() + 1)).slice(-2);
        str += month + " " + (+month % 12 == 0 ? date.getFullYear() + "\n" : "")
    }

    return str + date.getFullYear();
}
console.log (calRows()) /*
08 09 10 11 12 2010
01 02 03 04 05 06 07 08 09 10 11 12 2011
01 02 03 04 05 06 07 08 09 10 11 12 2012
01 02 03 04 05 06 07 08 2013 */

Heres a Fiddle

Or if you prefer, the same without assigning a new Date object in the loop.

function calRows() {
    var date,
        now = new Date(),
        first = new Date(now.getFullYear(), now.getMonth() -37, 1),
        monthYear = [first.getMonth(),first.getFullYear()]
        str = "";

    for (var i = -37;i++;) {
        month = ("0" + (++monthYear[0])).slice(-2);
        str += month + " " + (+month % 12 == 0 ? (monthYear[0]=0,monthYear[1]++) + "\n" : "")
    }

    return str + monthYear[1]
}

Answer 2

Check if this is what you want

function printCalendarRows(){
        var d = new Date();
        var o = new Date();
        o.setMonth( (d.getMonth()) - 36); //or   o.setFullYear( (d.getFullYear()) - 3);
        var currnt;
        while (o < d)
        {
          currnt = o.getMonth();
          console.log(currnt);
          if (currnt == 11)
          {
             console.log(o.getFullYear());
          }
          o.setMonth(currnt+1);

        }
        if (d.getMonth() != 11)
        {
           console.log(d.getFullYear());
        }
        alert("Date:"+ d + "Month:" + d.getMonth());
}

Answer 3

I would use momentjs :

function printCalendarRows(){
    var d = moment().subtract('months', 37);
    var y = d.format("YYYY");
    var n = moment().format("MM/YYYY");
    var log = "";
    while(d.format("MM/YYYY") != n) {
        if (d.format("YYYY") != y) {
            console.log(log + y + "\r\n");
            y = d.format("YYYY");
            log = "";
        }
        log += d.format("MM") + " ";
        d = d.add("months", 1);
    }
    console.log(log + d.format("YYYY"));
}

printCalendarRows();

working DEMO