NodeJs child_process 工作目录

Question

I am trying to execute a child process in a different directory then the one of its parent.

var exec = require('child_process').exec;

exec(
    'pwd',
    {
        cdw: someDirectoryVariable
    },
    function(error, stdout, stderr) {
        // ...
    }
);

I'm doing the above (though of course running "pwd" is not what I want to do in the end). This will end up writing the pwd of the parent process to stdout, regardless of what value I provided to the cdw option.

What am I missing?

(I did make sure the path passed as cwd option actually exists)

Answer 1

The option is short for current working directory , and is spelled cwd , not cdw .

var exec = require('child_process').exec;
exec('pwd', {
  cwd: '/home/user/directory'
}, function(error, stdout, stderr) {
  // work with result
});

Answer 2

If you're on windows you might choke on the path separators. You can get around that by using the join function from the built-in Node.js path module. Here is @hexacyanide's answer but with execSync and join instead of exec (which doesn't block the event loop, but not always a huge deal for scripts) and Unix file paths (which are cooler and better than Window file paths).

const { execSync } = require('child_process');
const { join } = require('path');
exec('pwd', { cwd: path.join('home', 'user', 'directory') });