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jQuery / AJAX更新表上的链接/按钮单击

[英]Jquery / AJAX update table on link / button click

I have a table populated from MySQL, I'm trying to update values by a click of a button, but I'm not really sure where to start. 我有一个从MySQL填充的表,我试图通过单击按钮来更新值,但是我不确定如何从哪里开始。

I am just getting into Jquery / AJAX, and haven't really figured it out quite yet so don't be too harsh on me. 我只是进入Jquery / AJAX,还没有真正弄清楚它,所以不要对我太苛刻。

In my example I have a HTML table that looks like this: 在我的示例中,我有一个如下所示的HTML表:

ID   Status      Set Status
1    Pending     Yes / No
2    Pending     Yes / No
3    Pending     Yes / No
4    Pending     Yes / No
5    Pending     Yes / No

Now when I click on ID 3 Yes, MySQL entry with ID 3 should be updated to Yes 现在,当我点击ID 3是的,与MySQL入门ID 3应更新Yes

My question is, how do I find out which Yes / No of which row was clicked ? 我的问题是,如何找出单击的Yes / No的哪一行? How do I pass that to the processing script via AJAX ? 如何通过AJAX将其传递给处理脚本?

My Yes / No Links have the ID of the entry attached like so: 我的Yes / No链接的条目ID如下所示:

<a href="status.php?set=yes&id=3">

I'm fine with the PHP part I think, my problem is getting the correct data to it. 我认为PHP部分很好,我的问题是要获取正确的数据。

//Edit, this is the table: //编辑,这是表:

<table class="table table-striped table-bordered table-hover datatable">
       <thead>
         <tr>
           <th><div class="checkbox"><input type="checkbox" /></div></th>
           <th>ID</th>
           <th>Status</th>
           <th>Set Status</th>
         </tr>
       </thead>
<tbody>
<?php 
      $query=mysql_query( "select * from test");
      if(mysql_num_rows($query)>0){
      while($data=mysql_fetch_array($query,1)){
?>
<tr>
  <td><div class="checkbox"><input type="checkbox" /></div></td> 
  <td><?php echo $data['id']; ?></td>
  <td>
  <?php 
  if($data['status'] == 'pending') 
  { 
       echo "<span class=\"label label-warning\">Pending</span>";
  } 
  elseif($data['status'] == 'yes') 
  { 
      echo "<span class=\"label label-success\">Yes</span>";
  } 
  elseif($data['status'] == 'no') 
  { 
    echo "<span class=\"label label-danger\">No</span>";
  } 
  ?></td>
  <td>
  <?php 
  if($data['status'] == 'pending') 
  { 
      echo "<a href=\"" . "status?set=yes&id=" . $data['id'] ."\" class=\"btn btn-success btn-xs\"><i class=\"icon-ok-sign\"></i> Yes</a>" . " <a href=\"" . "status?set=no&id=" . $data['id'] ."\" class=\"btn btn-danger btn-xs\"><i class=\"icon-remove\"></i>No</a>"; 
   } ?>
   </td>
   </tr>
   <?php 
          }
     } ?>
   </tbody>
   </table>

/// EDIT 2 ///编辑2

Utilizing user574632's answer, I got the simple AJAX GET to work as to updating the table, now I'm trying to get some feedback posted back to the user and hiding the 2 buttons. 利用user574632的答案,我得到了用于更新表的简单AJAX GET,现在我试图将一些反馈发布回用户并隐藏2个按钮。

status.php status.php

$id = $_GET['id'];
$status = $_GET['set'];

if($_GET['set'] == 'yes') {
$result = mysql_query("UPDATE test SET status='yes' WHERE id='$id'") 
or die(mysql_error()); 
echo "Status Changed to Yes";
exit();  }

if($_GET['set'] == 'no') {
$result = mysql_query("UPDATE test SET status='no' WHERE id='$id'") 
or die(mysql_error()); 
echo "Status Changed to No";
exit();  }

Whilst you probably want to display some kind of feedback to the user, this simplest way to acheive this would be like so: 虽然您可能想向用户显示某种反馈,但是实现这一目标的最简单方法是这样的:

$('#tableid a').click(function(){
    event.preventDefault();
    var href = $(this).attr('href');
    $.get( href );
})

provided the html table has an id='tableid'. 如果html表具有id ='tableid'。

What this does is stop the link being followed, then grap the href attribute, and perform a get request via ajax. 这样做是停止跟踪链接,然后获取href属性,并通过ajax执行获取请求。

You would probably want to indicate success/fail etc, but without seeing your status.php i cant elaborate 您可能希望指示成功/失败等,但是没有看到您的status.php,我无法详细说明

EDIT per comment: To get data back from the php file: 按评论编辑:要从php文件中获取数据,请执行以下操作:

 $('#tableid a').click(function(){
    event.preventDefault();
    var href = $(this).attr('href');

    $.get( href, function( data ) {
        //append data to a div, hide buttons etc.
        //alert used as example
        alert( data );
    });
 });

Y ÿ

Added class to your anchor tag so it will look like <a class="mylink" href="status.php?set=yes&id=3"> 在您的锚标记中添加了类,因此其外观类似于<a class="mylink" href="status.php?set=yes&id=3">

Now add a jquery to initiate ajax request when you click on the link. 现在,当您单击链接时,添加一个jquery以启动ajax请求。 This is how your jquery should be. 这就是您的jquery应该是的样子。

jQuery(document).ready(function($){
    $(".mylink").click(function(e) {
        $.post($(this).attr(),{},function(res){
            console.log(res);
        });
        return false;
    });
});

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