如何在ASP.NET MVC 4中显示从模型到另一个视图的列表

Question

I have a list of Topic 's. Each Topic have a list of Message . When i click on "Details" I want to open a new View that display a list of the Message 's from the Topic.

I expect that I need to modify this line: (this is what I have so far)

@Html.ActionLink("Details", "Details", new { id=item.Id }, null)

The Message 's are accessed by item.Message .

And the first line in the Detail View

@model IEnumerable<Models.TopicMessage>

---

This is my Topic View:

 @model IEnumerable<Models.Topic> <table> <tr> <th> @Html.DisplayNameFor(model => model.Name) </th> <th></th> </tr> @foreach (var item in Model) { <tr> <td> @Html.DisplayFor(modelItem => item.Name) </td> <td> @Html.ActionLink("Details", "Details", new { id=item.Id }, null) </td> </tr> } </table> 

Answer 1

There are a number of ways to do that. You can use the Action method to execute the controller action directly:

<tr>
    <td>
        @Html.DisplayFor(modelItem => item.Name)
    </td>
    <td>
        @Html.Action("Details", "Details", new { id=item.Id })
    </td>
</tr>

Or you can bypass the controller and render the view directly using this overload of DisplayFor :

<tr>
    <td>
        @Html.DisplayFor(modelItem => item.Name)
    </td>
    <td>
        @Html.DisplayFor(modelItem => item.Messages, "MessagesDetail")
    </td>
</tr>

Or if you define the template as the default DisplayTemplate , you can just do this:

<tr>
    <td>
        @Html.DisplayFor(modelItem => item.Name)
    </td>
    <td>
        @Html.DisplayFor(modelItem => item.Messages)
    </td>
</tr>

Answer 2

I fixed this by making a somethingViewModel that contained both the liste and the Id. That way i could contain the two information from two difference places in one new object I had access to in the View.