[英]Dynamicly Converting Type Object to Type (Some Class)
I would like some of my methods take an Object
and convert it in to a useable type: 我希望我的一些方法获取一个
Object
并将其转换为可用类型:
*Simple example *简单的例子
public void PostAction (object act){
object Action = (act.GetType) act;
string ActionName = Action.PostName;
}
From doing a little looking around the internet and Stackoverflow, I have found only ways to call an object's methods without a type 通过稍微浏览一下互联网和Stackoverflow,我发现只有在没有类型的情况下调用对象方法的方法
public void PostAction (object act){
Type t = act.GetType(); // myObject.GetType() would also work
MethodInfo GetPostName = t.GetMethod("GetPostName");
GetPostName.Invoke(act, null);
}
Is there a better way? 有没有更好的办法? Can I cast a Object to its Type??
我可以将一个对象转换为它的类型??
You could use dynamic
: 你可以使用
dynamic
:
public void PostAction (object act){
((dynamic)act).GetPostName();
}
But I would go further and change the approach: 但我会进一步改变方法:
Declare interface with your GetPostName
method: 使用
GetPostName
方法声明接口:
public interface IMyInterface { void GetPostName(); }
Implement the interface in your class 在您的类中实现接口
Change PostAction
method to take IMyInterface
parameter: 更改
PostAction
方法采取IMyInterface
参数:
public void PostAction(IMyInterface act)
Use the interface method withing PostAction
method: 使用
PostAction
方法的接口方法:
public void PostAction(IMyInterface act) { act.GetPostName(); }
Benefits: 优点:
You should actually never use reflection to invoke a method of an object you pass in. And it is also not really best practice to use object as parameter type of a method. 实际上,您应该永远不要使用反射来调用传入的对象的方法。使用object作为方法的参数类型也不是最佳实践。 You usually want your code strongly typed.
您通常希望您的代码是强类型的。
Anyways, if you want "object" as the type of your parameter, simply cast the object to an interface or type: 无论如何,如果您希望“对象”作为参数的类型,只需将对象强制转换为接口或键入:
public interface IMyInterface
{
string GetPostName();
}
public void PostAction(object actObject)
{
var action = actObject as IMyInterface;
if (action != null)
{
var postName = action.GetPostName();
}
}
If you cast like this, the result can be null if the object does not implement that interface, thats why you might want to check against null... 如果像这样进行转换,如果对象没有实现该接口,结果可以为null,这就是为什么你可能要检查null ...
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