在页面中显示json结果
[英]Display json result in page
问题描述
I have the following js script and html codes and would like to output the result on a page. 
我有以下js脚本和html代码，并想在页面上输出结果。 When I run it in console I can see the results as follows: 当我在控制台中运行它时，我可以看到如下结果：
[Object { title="They didn't Bow; They didn't Burn", link="http://xxxxxxx.com/bow-burn/", author="Admin", more...}, Object { title="When last did you antic...ant areas of your life?", link="http://xxxxxxx...significant-areas-life/", author="Admin", more...}, Object { title="Marriage Is Honourable In All…", link="http://xxxxxxx...arriage-honourable-all/", author="Admin", more...}, Object { title="Dwelling In The Strongholds Of God", link="http://xxxxxxx...elling-strongholds- [对象{title =“他们没有鞠躬；他们没有燃烧”，link =“ http://xxxxxxx.com/bow-burn/”，author =“ Admin”，更多...}，对象{ title =“您最后一次滑稽的生活吗？”，链接=“ http：//xxxxxxx...significant-areas-life/”，author =“ Admin”，更多...}，对象{title =“婚姻在所有方面都是光荣的…”，link =“ http：//xxxxxxx...arriage-honourable-all/”，author =“ Admin”，更多...}，对象{title =“住宅在“上帝的堡垒”中，链接=“ http：//xxxxxxx...elling-strongholds-
html code: html代码：
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="utf-8">
<!-- Always force latest IE rendering engine (even in intranet) & Chrome Frame
Remove this if you use the .htaccess -->
<meta http-equiv="X-UA-Compatible" content="IE=edge,chrome=1">
<script src="css/style.css"></script>
<link rel="stylesheet" href="http://code.jquery.com/mobile/1.3.2/jquery.mobile-1.3.2.min.css" />
<script src="http://code.jquery.com/jquery-1.9.1.min.js"></script>
<script src="http://code.jquery.com/mobile/1.3.2/jquery.mobile-1.3.2.min.js"></script>
<script src="js/script.js"></script>
</head>
<body>
<div id="blog" data-role="page">
<div data-role="header" class="sys_hd" data-position="fixed" data-id="sys_header" >
<h1>Sysads Posts</h1>
</div><!-- header -->
<div data-theme="c" data-role="content" id="postlist"> </div><!-- content -->
<div data-role="footer" data-position="fixed" data-id="sys_footer" >
<div data-role="navbar" >
<ul>
<li><a href="#blog" class="sys_ft">Home</a></li>
<li><a href="#blog" class="sys_ft">Disclaimer</a></li>
</ul>
</div><!-- navbar -->
</div><!-- footer -->
</div><!-- page -->
</body>
</html>
js code: js代码：
$(document).ready((function(){
url = 'http://xxxxxxxx.com/category/daily-devotion/feed/';
$.ajax({
type: "GET",
url: document.location.protocol + '//ajax.googleapis.com/ajax/services/feed/load?v=1.0&num=1000&callback=?&q=' + encodeURIComponent(url),
dataType: 'json',
error: function(){
alert('Unable to load feed, Incorrect path or invalid feed');
},
success: function(xml){
postlist = xml.responseData.feed.entries;
console.log(postlist);
}
});
}));
5 个解决方案
解决方案1
1 2013-09-23 13:02:18
It may be malformed json. json格式可能不正确。 What does http://json.parser.online.fr/ say? http://json.parser.online.fr/说什么？
解决方案2
0 2013-09-23 13:03:54
试试stringfy方法：
JSON.stringfy(obj)
解决方案3
0 2013-09-23 13:07:48
try : 尝试：
for(var i in postlist) {
var obj = postlist[i];
console.log("title >>> "+obj.title);
console.log("link>>> "+obj.link);
...........//other properties
}
解决方案4
0 2013-09-23 13:11:28
It isn't entirely clear from your question what you are trying to accomplish, but from the title and the provided code, I'm guessing you want to add the retrieved entries to the '#postlist' part of your page. 从您的问题中尚不清楚您要完成什么，但是从标题和提供的代码来看，我猜您想将检索到的条目添加到页面的“ #postlist”部分。 If that is right, you could do something like this: 如果正确，则可以执行以下操作：
success: function(xml){
postlist = xml.responseData.feed.entries;
$.each(postlist, function(entry){
$('#postlist').append($('<div class="entry">' + entry.title + '</div>'));
});
}
And obviously add whatever else you like markup-wise. 显然，添加其他您喜欢的标记方式。
Hope that helps. 希望能有所帮助。
解决方案5
0 已采纳 2013-09-28 19:45:53
Try this: 尝试这个：
success: function(data ){
var postlist = data.responseData.feed.entries;
var html = '<ul data-role="listview" data-filter="true">' ;
for (var i = 0 ; i < 10 ; i++) {
var entry = postlist[i];
html += '<li>';
html += '<a href="' + entry.link + '">' ;
html += '<div>' + entry.title + '</div>' ;
html += '<div>' + entry.author + '</div>' ;
html += '</a>';
html += '</li>';
}
html += '</ul>';
$( "#postlist" ).append(html);
}});
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