简体   繁体   English

在iOS 7中使用superview获取UITableViewCell

[英]Getting UITableViewCell with superview in iOS 7

I'm getting the UITableViewCell a UIButton belongs to like this: 我得到的UITutView属于UIButton属于这样:

-(void)buttonHandler:(UIButton *)button {

    OrderCell *cell = [[button superview] superview];
    NSLog(@"cell.item = %@", cell.item.text);

And it works fine in anything before iOS 7. But gives me: 在iOS 7之前它可以正常工作。但是给了我:

[UITableViewCellScrollView item]: unrecognized selector sent to instance 0x17ae2cf0 [UITableViewCellScrollView item]:无法识别的选择器发送到实例0x17ae2cf0

if I run the app in iOS 7. BUT if I do: 如果我在iOS 7中运行该应用程序。但如果我这样做:

-(void)buttonHandler:(UIButton *)button {

    OrderCell *cell = [[[button superview] superview] superview];
    NSLog(@"cell.item = %@", cell.item.text);

Then it works in iOS 7 but not earlier?!?!?! 然后它可以在iOS 7中运行,但不是更早???!?!

I'm circumventing the issue by doing this: 我这样做是在绕过这个问题:

OrderCell *cell;
if([[[UIDevice currentDevice] systemVersion] isEqualToString:@"7.0"])
    cell = [[[button superview] superview] superview];
else
    cell = [[button superview] superview];

NSLog(@"cell.item = %@", cell.item.text);

but WTF is going on!? 但是WTF还在继续!? Does anyone know why this happens? 有谁知道为什么会这样?

Thanks! 谢谢!

A better solution is to add a category for UIView(SuperView), and calling it by: 更好的解决方案是为UIView(SuperView)添加一个类别,并通过以下方式调用它:

UITableViewCell *cell = [button findSuperViewWithClass:[UITableViewCell class]]

This way, your code works for all future and past iOS versions 这样,您的代码适用于所有未来和过去的iOS版本

@interface UIView (SuperView)

- (UIView *)findSuperViewWithClass:(Class)superViewClass;

@end


@implementation UIView (SuperView)

- (UIView *)findSuperViewWithClass:(Class)superViewClass {

    UIView *superView = self.superview;
    UIView *foundSuperView = nil;

    while (nil != superView && nil == foundSuperView) {
        if ([superView isKindOfClass:superViewClass]) {
            foundSuperView = superView;
        } else {
            superView = superView.superview;
        }
    }
    return foundSuperView;
}
@end

The best way to do this is: 最好的方法是:

CGPoint buttonPosition = [sender convertPoint:CGPointZero toView:self.tableView];
NSIndexPath *indexPath = [self.tableView indexPathForRowAtPoint:buttonPosition];
UITableViewCell *cell = (UITableViewCell*)[self.tableView cellForRowAtIndexPath:indexPath];

To complete the answer of @thomas-keuleers this is the swift method: 要完成@ thomas-keuleers的答案,这是一个快速的方法:

extension UIView {

    func findSuperViewWithClass<T>(superViewClass : T.Type) -> UIView? {

        var xsuperView : UIView!  = self.superview!
        var foundSuperView : UIView!

        while (xsuperView != nil && foundSuperView == nil) {

            if xsuperView.self is T {
                foundSuperView = xsuperView
            } else {
                xsuperView = xsuperView.superview
            }
        }
        return foundSuperView
    }

}

and you simply call like that: 而你只是这样打电话:

child.findSuperViewWithClass(TableViewCell)

A shorter Version in swift 5 swift 5中的较短版本

extension UIView {
   var xsuperView = self.superview

   while xsuperView != nil {
        if let superView = xsuperView.self as? T {
            return superView
        } else {
            xsuperView = xsuperView?.superview
        }
    }
}
if ([[button superView] isKindOfClass:[UITableViewCell class]]) {

}

else //check next :

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM