jQuery-选择所有以...开头的属性名称（不是值）的元素？

Question

Say I'm looking for all elements with an attribute 'data-language', whose value begins with 'java' (would match both 'java' and 'javascript'). I know how to do this:

$('[data-language^="java"]')

But my question is: how do I get all elements that have an attribute ( not the value of the attribute, but the actual attribute name itself ) beginning with something? For example:

1. all elements that have an attribute name beginning with "data-s", or
2. all elements that have data attributes at all (attributes beginning with "data-").

Answer 1

There is no shortcut, you may use the attributes collection :

 $(someselector).filter(function(){
      var attrs = this.attributes;
      for (var i=0; i<attrs.length; i++) {
          if (attrs[i].name.indexOf("someStartOfName")==0) return true;
      }         
      return false;
 });

Answer 2

jQuery has a nice function for this.

http://api.jquery.com/data/

$("div").data() // returns all data attributes to this div